[英]Python + BeautifulSoup - Text extraction by searching criteria
A file contains HTML codes like below (the words 'Registration' and 'Flying' are fixed in the following paragraphs): 一个文件包含如下所示的HTML代码(以下段落中固定了“ Registration”和“ Flying”一词):
<TR>
<TD class=CAT2 width="10%">Registration</TD>
<TD class=CAT1 width="20%">02 Mar 2006</TD></TR>
<TR>
<TD class=CAT2 width="10%">Flying</TD>
<TD class=CAT1 width="20%">24 Jun 2005</TD></TR>
I want to extract them and put as: 我想提取它们并放入:
Registration 02 Mar 2006
注册2006年3月2日
Flying 24 Jun 2005
飞行2005年6月24日
I am using the BeautifulSoup find_next_sibling however it returns nothing. 我正在使用BeautifulSoup find_next_sibling但是它什么也不返回。 What's went wrong?
怎么了
from bs4 import BeautifulSoup
url = r"C:\example.html"
page = open(url)
soup = BeautifulSoup(page.read())
aa = soup.find_next_sibling(text='Registration')
print aa
尝试这个
soup.find(text="Registration").findNext('td').contents[0]
This line of code: 这行代码:
aa = soup.find_next_sibling(text='Registration')
is not returning a node in the HTML as you are expecting it would. 没有像您期望的那样在HTML中返回节点。 Instead it is returning a
NoneType
. 相反,它返回一个
NoneType
。 What you want to do instead is, find the element with text='Registration'
get it's parent and get the parent's next sibling. 相反,您要做的是找到带有
text='Registration'
的元素,使其成为父级,并获取父级的下一个同级。
aa = soup.find(text='Registration')
par = aa.parent
print par.next_sibling.string
You could also achieve your output as: 您还可以通过以下方式实现输出:
soup = BeautifulSoup(page.read())
row_1 = soup.find('tr')
td = row_1.find('td')
string_1 = td.string + ' ' + td.next_sibling.string #Registration 02 Mar 2006
row_2 = row_1.next_sibling
td = row_2.find('td')
string_2 = td.string + ' ' + td.next_sibling.string #Flying 24 Jun 2005
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.