如何使用Javascript获取所有孩子（即孩子的孩子）？

Question

I need a javascript function or a CSS Selector (or even a ProtoypeJS function) which gets me ALL elements (ie. descendants) under a particular element.

I understand there are CSS selectors such as : 'p, a, div' , which would get me all the elements of those three types. However I need to get EVERYTHING without specifying type.

ie. I want something like

myElement.getElements('*')

Answer 1

You can use querySelectorAll

myElement.querySelectorAll('*')

Note: Supported in IE8+

Answer 2

Compatible with all versions of IE, not just IE8+...

myElement.getElementsByTagName("*")

* is treated as a special case for getElementsByTagName to return all descendants regardless of tag name. (This is different to querySelectorAll , where * is a genuine selector that matches all elements)

Answer 3

The method that will get you all child elements as an extended PrototypeJS array is childElements() http://api.prototypejs.org/dom/Element/prototype/childElements/

element.childElements()

For other situations you might want to narrow down the child elements that are returned you can use select()

element.select('div')

will return all the div children of element

Answer 4

It's easy enough to do this with CSS alone. The * (universal) selector targets all elements. If you want to target all children of a specific element , then you can simply do this:

element * {}