jQuery-获取URL路径的中间部分

Question

URL Examples:

http://www.demotest.com/categoey/t23
http://demotest.com/categoey/t23
http://www.demotest.net/categoey/c24

I only want " demotest " portion from above URL (using jquery and JavaScript )

Using window.location.hostname I got full path www.demotest.com but i want only demotest part

Answer 1

You could use this regular expression:

\.([^.]+)\.[^.]+$

http://regex101.com/r/eM7oQ0

Or you could split:

var domain = window.location.hostname.split('.');
console.log(domain[domain.length - 2]);

http://jsfiddle.net/jyWYu/

Answer 2

Try using split,

urlParts = window.location.hostname.split('.');
urlParts[urlParts.length-1]

Answer 3

Try window.location.hostname.split('.')[0]

more at Extract hostname name from string

Answer 4

Split it by "." like so:

var str = "www.demotest.com"
var arrStr = str.split(".");

Then what you want will be at index 1 - arrStr[1]

Here is jsFiddle - http://jsfiddle.net/N0ir/yLtCW/