javascript获取执行环境

Question

I need to get the execution environment of JS code. if it is a console or if it browser. How should I approach this?

for instance:

if(exec_type() == 'browser')
{
 // do something
}

What is the purpose of it? I want to add some functionality if the code is not run from a console such as firebug, and to disable them when it is run from console environment.

Answer 1

You can use this simple function:

function isInWindow() {
  return this === window;
}

It will return true if script is running in window namespace (browser).

Here is jsfiddle

Answer 2

Maybe these functions will help you.

function isInWindow(){
  if(typeof window === "object"){
    return true;  
  }else{
    return false;
  }
}
function isInNode(){
  if(typeof global === "object"){
    return true;  
  }else{
    return false;
  }
}
console.log(isInWindow); // true, if in browser
console.log(isInNode);  // true, if in node.js

Here is JS Bin