c程序以进程为背景而永不死？

Question

int daemon()
{
if (daemon(1, 1) < 0) /* Keep the same working directory and pipes */
{


             makeTimer("First Timer", &firstTimerID, 2, 2);   //2ms
             makeTimer("Second Timer", &secondTimerID, 10, 10);    //10ms
             makeTimer("Third Timer", &thirdTimerID, 100, 100);  //100ms
    return 1;
              }
    }




 int main()
{
daemon();
}


           return 0;

         }

I created a timer and the timer is calling the task for every 2ms, 10ms and 100ms. I want to run the timer in the background and it should never die. Could anyone give me some ideas in c program to run the task in the background for linux operating system. I want to make this three calls to run in the back ground :

   makeTimer("First Timer", &firstTimerID, 2, 2);   //2ms
   makeTimer("Second Timer", &secondTimerID, 10, 10);    //10ms
   makeTimer("Third Timer", &thirdTimerID, 100, 100);  //100ms

Answer 1

Try the daemon() function in C from unistd.h . It makes it easy to detach yourself from the terminal and run in the background.

It's as simple as

if (daemon(1, 1) < 0) /* Keep the same working directory and pipes */
{
     perror("daemon");
     return 1;
}

and just put that in your main function

Answer 2

You could call your script using the nohup command. Simply run your script on the command line as follows nohup <myscript>

It may be what you really want is to create a cron job, however. Check docs for your linux distro to find out more.