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SQL选择列中的唯一值

[英]SQL Select for unique value in a column

I have a table like 我有一张桌子

| ID | COL1 | COL2 |
| 1  |   1  |  w   |
| 1  |   2  |  x   |
| 2  |   1  |  y   |
| 2  |   2  |  z   |

When I query it, I'd like to get 当我查询它时,我想得到

| ID | COL2:1 | COL2:2 |    <--- (when COL1=1 and COL1 =2)
| 1  |   w    |    x   |
| 2  |   y    |    z   |

I've tried GROUP BY and JOIN for the same table but I get duplicates and not grouped data. 我已经为同一个表尝试了GROUP BYJOIN ,但是我得到了重复项而不是分组数据。 I need some pointers for how to get the results I'm expecting. 我需要一些指导,以了解如何获得我期待的结果。

You can use MAX() and a CASE statement for this: 您可以使用MAX()CASE语句:

SELECT ID
      ,MAX(CASE WHEN Col1 = 1 THEN Col2 END) AS Col2_1
      ,MAX(CASE WHEN Col1 = 2 THEN Col2 END) AS Col2_2
FROM YourTable
GROUP BY ID

Demo: SQL Fiddle 演示: SQL小提琴

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