[英]How to order by column not in select clause?
Is there a method to work around not being able to sort by a column not in the select clause? 有没有一种方法可以解决无法按select子句中的列排序的问题? I am using datename to grabe month and year, but i need it to be sorted by actual date not alphabetically. 我使用日期名称来获取月份和年份,但我需要按实际日期而不是按字母顺序对其进行排序。
select datename(month, dbo.ITR.ITR_TransDate) as MonthDt,
DATENAME(year, dbo.itr.ITR_TransDate) as YearDt, COUNT(distinct dbo.ITR.ITR_Reason) AS WKCount, COUNT(dbo.itr.itr_reason) AS LineCt
from dbo.ITR
where (ITR_EmployeeID IN (N'robra', N'lewer', N'petam', N'whike', N'mclch', N'ricju')) AND (dbo.ITR.ITR_TransDate >= '1/1/13' AND dbo.itr.ITR_TransDate <= '1/31/14') AND
(dbo.itr.ITR_Reason LIKE 'WO%' OR dbo.itr.ITR_Reason LIKE 'RW%')
group by DATENAME(year, dbo.itr.ITR_TransDate), datename(month, dbo.ITR.ITR_TransDate), MONTH(dbo.itr.itr_transdate)
order by dbo.ITR.ITR_TransDate
the order by i have is failing b/c it isn't in the group by or an aggregate. 我所拥有的订单无法通过b / c预订,因此不在分组依据中或不在汇总中。 i can't add it to either b/c there are many many dates that it would return. 我不能将其添加到任何一个B / C中,它将返回许多日期。
You can just use an aggregation function in the order by
: 您可以按以下order by
使用聚合函数:
order by min(dbo.ITR.ITR_TransDate)
This should work for your case. 这应该适合您的情况。
try this 尝试这个
select datename(month, dbo.ITR.ITR_TransDate) as MonthDt,
DATENAME(year, dbo.itr.ITR_TransDate) as YearDt, COUNT(distinct dbo.ITR.ITR_Reason) AS WKCount, COUNT(dbo.itr.itr_reason) AS LineCt
from dbo.ITR
where (ITR_EmployeeID IN (N'robra', N'lewer', N'petam', N'whike', N'mclch', N'ricju')) AND (dbo.ITR.ITR_TransDate >= '1/1/13' AND dbo.itr.ITR_TransDate <= '1/31/14') AND
(dbo.itr.ITR_Reason LIKE 'WO%' OR dbo.itr.ITR_Reason LIKE 'RW%')
group by DATENAME(year, dbo.itr.ITR_TransDate), datename(month, dbo.ITR.ITR_TransDate), MONTH(dbo.itr.itr_transdate)
order by DATENAME(year, dbo.itr.ITR_TransDate), MONTH(dbo.itr.itr_transdate)
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