[英]Breaking out of one JS function to call another JS function
Let's say that I have a series of functions: 假设我有一系列功能:
function a(){
//do this, do that
b();
}
function b(){
//do this, do that
c();
}
function c(){
//do this, do that
// program ends at this point
}
a();
You would assume that from executing the code, we go from a()
to b()
to c()
and the program terminates... 您将假设执行代码后,我们从
a()
到b()
再到c()
,程序终止了……
What I'm wondering is... is it possible to place code somewhere within the // do this, do that
part of b()
that depending on certain conditions to return to a()
and then proceed through without the need of returning where it left off in b()
, although if needed could then launch b()
afresh? 我想知道的是...是否可以将代码放置在
// do this, do that
内的某个位置, // do this, do that
b()
那部分工作b()
取决于某些条件,然后返回到a()
,然后继续进行而无需返回它在b()
保留的位置,但是如果需要的话可以重新启动b()
?
I know, what you're thinking... "This is a JavaScript GOTO
question, surely!" 我知道,您在想什么……“肯定是JavaScript
GOTO
问题!” and to a degree it is... but seriously, is it possible to break from a function A completely and go to function B without having to worry about it returning to function A to finish where it left off? 并在某种程度上是……但很严重,是否有可能完全脱离功能A而转到功能B,而不必担心它会返回功能A以结束它的停止?
You can use JavaScript's return
statement like this 您可以像这样使用JavaScript的
return
语句
function a(){
//do this, do that
b();
}
function b(){
if (some_random_condition) {
return;
}
c();
}
a();
The return
statement makes it possible to go to a
without having to execute the rest of b
function. return
语句可以转到a
而不必执行b
功能的其余部分。
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