Java Split Regex Patten字母和数字

Question

I want to split this regexp pattern 2 numbers-3 numbers-5 numbers and letter in two part. Numbers and "-" one array and the letters in the second array.

I been trying to figure it out for a while. Hoping I can get some help.

Here is an example

"12-123-12345A"    <----- the string 
// I want to split it such that it can be ["12-123-12345","A"]

I tried this

"\\d{2}-\\d{3}-\\d{5}" 
// that only give me ["", "A"]

and this

"(?<=\\D)(?=\\d)|(?<=\\d)(?=\\D)"
// ["12", "-", "123", "-", "12345", "A"]

Answer 1

\\D matches any non-digit character (including - ). You'd better to use [^-\\d] instead to exclude - .

String s = "12-123-12345A";
String parts[] = s.split("(?<=\\d)(?=[^-\\d])");
System.out.println(parts[0]); // 12-123-12345
System.out.println(parts[1]); // A

See a demo: http://ideone.com/emr1Kq

Answer 2

尝试这个

String[] a = "12-123-12345A".split("(?<=\\d)(?=\\p{Alpha})");

Answer 3

(\\d{2}-\\d{3}-\\d{5})(\\w)

You can test it on this website

http://regexpal.com/

Here's the java code. note double slash in replace of slash \\ --> \\\\

package com.company;

import java.util.regex.Matcher;
import java.util.regex.Pattern;

// http://stackoverflow.com/questions/22061614
public class Main {

    public static void main(String[] args) {
      Pattern regex = Pattern.compile("(\\d{2}-\\d{3}-\\d{5})(\\w)");
      Matcher matcher = regex.matcher("12-123-12345A");
      matcher.find();
      System.out.println(matcher.group(1));
      System.out.println(matcher.group(2));
    // write your code here
    }
}