使用UIKeyCommand检测删除密钥

Question

任何人都知道如何在iOS 7上使用UIKeyCommand检测“删除”键？

Answer 1

As people were having problems with Swift, I figured a small, complete example in both Objective C and Swift might be a good answer.

Note that Swift doesn't have a \\b escape character for backspace, so you need to use a simple Unicode scalar value escape sequence of \\u{8}\u003c/code> . This maps to the same old-school ASCII control character number 8 ("control-H", or ^H in caret notation ) for backspace as \\b does in Objective C.

Here's an Objective C view controller implementation that catches backspaces:

#import "ViewController.h"

@implementation ViewController

// The View Controller must be able to become a first responder to register
// key presses.
- (BOOL)canBecomeFirstResponder {
    return YES;
}

- (NSArray *)keyCommands {
    return @[
        [UIKeyCommand keyCommandWithInput:@"\b" modifierFlags:0 action:@selector(backspacePressed)]
    ];
}

- (void)backspacePressed {
    NSLog(@"Backspace key was pressed");
}

@end

And here's the equivalent view controller in Swift:

import UIKit

class ViewController: UIViewController {

    override var canBecomeFirstResponder: Bool {
        return true;
    }

    override var keyCommands: [UIKeyCommand]? {
        return [
            UIKeyCommand(input: "\u{8}", modifierFlags: [], action: #selector(backspacePressed))
        ]
    }

    @objc func backspacePressed() {
        NSLog("Backspace key was pressed")
    }

}

Answer 2

很简单 - 需要查找退格字符“\\ b”

Answer 3

You can always try UIKeyInput. https://developer.apple.com/library/prerelease/ios/documentation/UIKit/Reference/UIKeyInput_Protocol/index.html#//apple_ref/occ/intfm/UIKeyInput/deleteBackward

The function should be

- (void)deleteBackward