mySQL转PHP动态表

Question

This question has been asked many times but I'm sorry I still can't make it work. I have a simple mySQL DB like this table:

In this DB I have a column with people and 3 other columns that represent days - Day 1, Day 2 and Day 3. The letter "M" means Morning and "A" Afternoon. So I want to query this DB and ask: "Who was working Day 1 in the morning?" and it returns "John". I know how to do this query, but I don't know how to format the return. Let's say that 3 people worked Day 1 morning (because the actual DB is bigger then this one) I want the HTML to return a 3 row table stating their names, but if only 2 persons worked Day one in the morning, it would return only a 2 row table stating their names.

This is my PHP:

<?php
    $con = mysql_connect(".",".",".");
    $db_selected = mysql_select_db("xbizh_14391723_horario", $con);

    $sql = "SELECT  `AM` FROM HORARIO WHERE  `1` ='N'";

    $result = mysql_query($sql);
    $num = mysql_numrows($result);


    if (!$result) {
        $message  = 'Invalid query: ' . mysql_error() . "\n";
        $message .= 'Whole query: ' . $query;
        die($message);
     }

    while($row = mysql_fetch_array($result))
    {
        print_r($row);
    }

    mysql_free_result($result);

?>

Answer 1

It seems to me you are most of the way there already.

print("<table>");

while($row = mysql_fetch_array($result))
{
    print("<tr><td>" . $row['name_field'] . "</td></tr>");
}

print("</table>");

You also need to make sure your query is returning the name field.

$sql = "SELECT * FROM HORARIO WHERE  `1` ='N'";

or

$sql = "SELECT `name_field` FROM HORARIO WHERE  `1` ='N'";