从最低到最高对多维数组进行排序，只有第一个元素保持未排序状态

Question

I've been playing around with this problem, trying to sort out this multidimensional array but I keep on getting the wrong output. The array is sorted, except for the first element. Everything is in order, apart from the first element in the array. The first element in the sorted array, is also the first element in the array before it's sorted, which is sNamesLongitude[0][0] .

The string sNamesLongitude[2][306] array has two rows. The first row holds the names of stations of the London underground, the second row holds its corresponding longitude. I'm trying to sort out the array so the stations with the lowest value for its longitude comes first in the array, and the last value will have the highest value for its longitude, while keeping their corresponding name (row 1), together with its longitude.

String[][] temp = new String[2][1];
    for (int a = 0; a < sNamesLongitude[0].length - 1; a++) {

        if ((Double.parseDouble(sNamesLongitude[1][a])) > (Double.parseDouble(sNamesLongitude[1][a + 1]))) {

            temp[0][0] = sNamesLongitude[0][a];
            temp[1][0] = sNamesLongitude[1][a];

            sNamesLongitude[0][a] = sNamesLongitude[0][a + 1];
            sNamesLongitude[1][a] = sNamesLongitude[1][a + 1];

            sNamesLongitude[0][a + 1] = temp[0][0];
            sNamesLongitude[1][a + 1] = temp[1][0];
            a=0;
        }

Answer 1

The problem is temp only has two elements temp[0][0] and temp[1][0]

your code -

sNamesLongitude[0][a + 1] = temp[0][a]; // Gets exception

a might go up to values greater than 1 (to 306, as per your question), hence the exception occurs.

Answer 2

After spending a whole day on it, the answer is: a should = -1, and not 0 at the end of the if block .

Can anyone please explain why though, is it something to do with scope?