避免gulp.dest并覆盖文件？

Question

I'm working on a large FS which I can't change:

/Javascript
/Javascript/FR
/Javascript/FR/FRA
/Javascript/FR/FRA/script1
/Javascript/FR/FRA/script1/Content
/Javascript/FR/FRA/script1/Content/script1.js
/Javascript/FR/FRA/script2
/Javascript/FR/FRA/script2/Content
/Javascript/FR/FRA/script2/Content/script2.js
[...]
/Styles
/Styles/FR
/Styles/FR/FRA
/Styles/FR/FRA/style1
/Styles/FR/FRA/style1/Content
/Styles/FR/FRA/style1/Content/style1.scss
/Styles/FR/FRA/style1/Content/img/svg1.svg
/Styles/FR/FRA/style2
/Styles/FR/FRA/style2/Content
/Styles/FR/FRA/style2/Content/style2.scss
/Styles/FR/FRA/style2/Content/img/svg2.svg
[...]

There are more than 100 directories which I CAN'T and DON'T want to concatenate.

My Gulpfile.js sits in the root (/) and tasks are run from there.

I'd like to avoid the destination-path pipe I use into gulp-imagemin , gulp-svgmin or gulp-ruby-sass tasks:

.pipe(gulp.dest('dist')) 

[...] and directly override my files with some suffix added before:

.pipe(rename({suffix: "-min"}))

I don't see a workaround with path/cwd or glob-stream.

Is there a way to keep gulping into the current working directory instead of a destination and get some overriding like:

[...]
/Styles/FR/FRA/style2
/Styles/FR/FRA/style2/Content
/Styles/FR/FRA/style2/Content/style2.scss
/Styles/FR/FRA/style2/Content/style2.css
/Styles/FR/FRA/style2/Content/img/svg2.svg
/Styles/FR/FRA/style2/Content/img/svg2-min.svg

Thanks for your help, here's my gulpfile.js: https://gist.github.com/aurelienlewin/9251972

Answer 1

必须是一些gulp-ruby-sass问题： https : //github.com/sindresorhus/gulp-ruby-sass/issues/27