[英]Ajax call gives response, but success,complete and error functions not firing
I'm trying to get sql results from a database through ajax call and display in another php page. 我试图通过ajax调用从数据库中获取sql结果,并显示在另一个php页面中。 My ajax call is: 我的ajax调用是:
function newfunc(){
start += 10;
var params = parseURLParams(document.URL);
var datastring = "nextStart="+start+"&subID="+params["hidSubjectID"]+"&topic="+params["hidTopic"];
if(datastring!=''){
$.ajax({
type:"POST",
url:"ajax/getTopicQuestions.php",
data: datastring,
dataType: "json",
success: function(json){ console.log("success"+json[0].question); alert("success");},
complete: alert("complete"),
error: alert("error")
});
}
} }
My json response has following format: 我的json响应具有以下格式:
[ { "qno": "3", "qbit": "(i)", "qinstruction": "", "question": "This is a question", "mark": "5", "examname": "B.Tech. Sixth Semester Examination", "examyear": "2011", "questionid": "368", "examtype": "BPUT Univ Exam", "topic": "HTML" },...
This function returns a valid json response (as seen in Chrome DevTools). 此函数返回有效的json响应(如Chrome DevTools中所示)。 But none of the alert()
is executed. 但是没有任何alert()
执行。 But every time console shows successThis is a question
. 但是每次控制台显示成功时,这successThis is a question
。 I've scanned through several questions but none seems to resolve this particular issue. 我已经浏览了几个问题,但似乎都无法解决这个特定问题。 I want to display all the data in that json. 我想显示该json中的所有数据。 Any advice is greatly appreciated. 任何意见是极大的赞赏。
That is NOT how you code callbacks 那不是你编写回调的方式
complete: alert("complete"),
error: alert("error")
needs to be 需要是
complete: function() { alert("complete") },
error: function() { alert("error") }
Try this, add function(){}
试试看,添加function(){}
complete: function(){ alert("complete");},
error: function(){ alert("error");}
instead of 代替
complete: alert("complete"),
error: alert("error")
callback should be a function.so you need to call a function in callback complete and error or use anonymous function like you did in success callback. 回调应该是一个函数,因此您需要在完成回调和出错时调用函数,或者像成功回调一样使用匿名函数。
complete: function(){ alert("complete");},
error: function(){ alert("error");}
api Doc: https://api.jquery.com/jQuery.ajax/ api文件: https : //api.jquery.com/jQuery.ajax/
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.