[英]jQuery datatable in MVC (server-side)
https://datatables.net/usage/server-side https://datatables.net/usage/server-side
On the page above, there are parameters that you need to receive to make server-side datatable work. 在上面的页面中,您需要接收一些参数以使服务器端数据表工作。 I have a helper class
我有一个助手班
public class TableParameter
{
public string sEcho { get; set; }
public int iDisplayStart { get; set; }
public int iDisplayLength { get; set; }
public int iSortingCols { get; set; }
}
But in order to sort columns I need to receive 但是为了排序我需要接收的列
string sSortDir_(int)
How do I do that? 我怎么做? I know (int) represents column ID that needs to be sorted, but I just can't catch it in my controller.
我知道(int)表示需要排序的列ID,但我无法在我的控制器中捕获它。
The datatable will post one or more sSortDir_x parameters to your controller, depending on how many columns are sorted on simultaneously in the table. 数据表将向控制器发布一个或多个sSortDir_x参数,具体取决于表中同时排序的列数。
The specific columns that the table is sorted by are sent in the iSortCol_ parameters (again, one or more). 表排序的特定列在iSortCol_参数中发送(同样,一个或多个)。
public class TableParameter
{
public string sEcho { get; set; }
public int iDisplayStart { get; set; }
public int iDisplayLength { get; set; }
public int iSortingCols { get; set; }
public int iSortCol_0 { get; set; } // the first (and usually only) column to be sorted by
public string sSortDir_0 { get; set; } // the direction of the first column sort (asc/desc)
public int iSortCol_1 { get; set; } // the second column to be sorted by
public string sSortDir_1 { get; set; } // the direction of the second column sort
// etc
}
For receiveing a column name in action, that is used for one-column sorting: 用于接收正在运行的列名称,用于单列排序:
public ActionResult SomeMethod(FormCollection coll)
{
var sortingColumnNumber = Convert.ToInt32(coll["iSortCol_0"]);
var sortingColumnName = coll[string.Format("mDataProp_{0}", sortingColumnNumber)];
var propertyInfo = typeof(SomeObject).GetProperty(sortingColumnName);
//..get List<SomeObject> sortedObjects
sortedObjects = sortedObjects.OrderBy(x => propertyInfo.GetValue(x, null)).ToList();
//...
}
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