在 C++ 中将字符串转换为数字

Question

I'm seeing a lot of options for converting a string to a number in C++.

Some of which are actually recommending the use of standard C functions such as atoi and atof .

I have not seen anyone suggesting the following option, which relies solely on C++ STL:

int Str2Num(const string& str) // can be called with a 'char*' argument as well
{
    int num;
    istringstream(str)>>num;
    return num;
}

Or more generally:

template <typename type>
type Str2Num(const string& str) // can be called with a 'char*' argument as well
{
    type num;
    istringstream(str)>>num;
    return num;
}

What are the disadvantages in the above implementation?

Is there a simpler / cleaner way to achieve this conversion?

Answer 1

Since C++11, we have hadstd::stoi :

std::stoi(str)

There is also std::stol and std::stoll .

Answer 2

In c++11 there's a number of numeric conversion functions defined in the std::string class itself:

Numeric conversions
stoi (C++11)
stol (C++11)
stoll (C++11)

converts a string to a signed integer

stoul (C++11)
stoull (C++11)

converts a string to an unsigned integer

stof (C++11)
stod (C++11)
stold (C++11)

converts a string to a floating point value

As for pre c++11 standards, I can't see any disadvantages from your template function sample.

Answer 3

你可以使用转换函数 Strtol() Strtoul() 但是在 C++11 中，你已经得到了上面的答案。

Answer 4

#include <sstream>
template <typename T>
inline bool StringToNumber(const std::string& sString, T &tX)
{
    std::istringstream iStream(sString);
    return !(iStream >> tX).fail();not
}

Then call

double num{};
StringToNumber(std::string{"580.8"}, num);

float fnum{};
StringToNumber(std::string{"5e+1.0"}, fnum);

Answer 5

 #include <iostream> #include <string> int main() { std::string str = "123"; int num; // using stoi() to store the value of str1 to x num = std::stoi(str); std::cout << num; return 0; }