[英]send email to recipient from .txt in python 3.3
I am trying to send an email with smtp in python 3.3 to a recipient listed in a text file. 我正在尝试将python 3.3中带有smtp的电子邮件发送给文本文件中列出的收件人。 The error I receive is:
我收到的错误是:
session.sendmail(sender, recipient, msg.as_string())
smtplib.SMTPRecipientsRefused: {}
session.sendmail(sender, recipient, msg.as_string())
smtplib.SMTPRecipientsRefused: {}
Where is the error in sendmail? sendmail中的错误在哪里? Thanks!
谢谢!
Full code below: 完整代码如下:
#!/usr/bin/python
import os, re
import sys
import smtplib
from email.mime.image import MIMEImage
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
mails = open('/path/emails.txt','r+')
mailList = mails.read()
mailList = [i.strip() for i in mails.readlines()]
directory = "/path/Desktop/"
SMTP_SERVER = 'smtp.gmail.com'
SMTP_PORT = 587
sender = 'Sender@gmail.com'
password = "Sender'sPassword"
recipient = [i.strip() for i in mails.readlines()]
subject = 'Python (-++-) Test'
message = 'Images attached.'
def main():
msg = MIMEMultipart()
msg['Subject'] = 'Python (-++-) Test'
msg['To'] = recipient
msg['From'] = sender
files = os.listdir(directory)
pngsearch = re.compile(".png", re.IGNORECASE)
files = filter(pngsearch.search, files)
for filename in files:
path = os.path.join(directory, filename)
if not os.path.isfile(path):
continue
img = MIMEImage(open(path, 'rb').read(), _subtype="png")
img.add_header('Content-Disposition', 'attachment', filename=filename)
msg.attach(img)
part = MIMEText('text', "plain")
part.set_payload(message)
msg.attach(part)
session = smtplib.SMTP(SMTP_SERVER, SMTP_PORT)
session.ehlo()
session.starttls()
session.ehlo
session.login(sender, password)
session.sendmail(sender, recipient, msg.as_string())
session.quit()
if __name__ == '__main__':
main()
You want to double-check your recipients code. 您要仔细检查您的收件人代码。 It looks like you're trying to consume the contents of the file more than once, which won't work--the file objects should be understood as a stream, not a block of data, so once you've done
f.read()
or [i.strip() for i in mails.readlines()]
one time, that stream is empty, so doing it a second time is going to produce an empty list. 看来您尝试不止一次使用文件的内容,这是行不通的-文件对象应被理解为流,而不是数据块,因此一旦完成
f.read()
或[i.strip() for i in mails.readlines()]
一次,该流为空,因此第二次执行将产生一个空列表。 You should check this yourself by printing recipient
您应该通过打印
recipient
自己检查一下
then try this: 然后试试这个:
mails = open('/path/emails.txt','r+')
#mailList = mails.read()
#mailList = [i.strip() for i in mails.readlines()]
directory = "/path/Desktop/"
SMTP_SERVER = 'smtp.gmail.com'
SMTP_PORT = 587
sender = 'Sender@gmail.com'
password = "Sender'sPassword"
recipient = [i.strip() for i in mails.readlines()]
print(recipient)
subject = 'Python (-++-) Test'
message = 'Images attached.'
Now you should have the a populated recipient list, and on to the next issue! 现在,您应该拥有一个已填充的收件人列表,然后继续下一期!
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