在Application.java中按名称返回结果视图

Question

In a Play 2.2! web project I'm pursuing, I'd like to return views by name in Application.java

I've added the following in the routes config :

GET     /:page                      controllers.Application.show(page: String)

And i'd like Application.java to return the correct view only using it's name (the String page).

At the moment I have :

public static Result show(String page) {
    switch(page){
        case "home":
            return ok(home.render());
        case "register":
            return ok(register.render());
    }
    return ok(home.render());
}

I'd like to avoid the switch statement here, and have show(String page) programatically find the view that matches the String page given in argument and return it (or home page if no match has been found).

EDIT : I've read some stuff about reflexion but I don't really know what that is or how to use it :/

Thanks for your insight :)

Answer 1

Remember that Play's view is a Scala function - which takes parameters, for ensuring typesafety , dynamic content etc, etc. In this scenario you shouldn't use :path argument but make usage of different routes to different actions like:

GET     /home           controllers.Application.home
GET     /register       controllers.Application.register

Actions:

public static Result home() {
    return ok(home.render());
}

public static Result register() {
    return ok(register.render());
}

Crypto-advertisment: Use Intellij - create templates for actions and routes and you will be doing it within milliseconds ;)

On the other hand if you have a large set of HTML files you can render them as... files instead of Play views like ( pseudo code, debug it yourself! )

public static Result show(String page) {

    File htmlFile = new File(page+".html");
    if (!htmlFile.exists()) htmlFile = new File("home.html");

    return ok(htmlFile).as("text/html");
}

I will only add that is absolutely NOT Play's way for working with templates ;)