[英]Data not entered into database from PHP
I am trying to enter data into a database with PHP. 我正在尝试使用PHP将数据输入数据库。
Here is my code: 这是我的代码:
<?php
$username = 'username'; //username for database
$password = 'password'; //password for database
$hostname = 'localhost'; //host
$db_name = 'db_testdrubin'; //name of database
$db_selected = mysqli_connect($hostname, $username, $password, $db_name)//specify database
or die ("unable to connect");
if(isset ($_POST['submit'])){
$ID = ($_POST['ID']);
$fname = ($_POST['fname']);
$lname = ($_POST['lname']);
$address = ($_POST['address']);
$city = ($_POST['city']);
$state = ($_POST['state']);
$zip = ($_POST['zip']);
$phone = ($_POST['phone']);
$email = ($_POST['email']);
$books = ($_POST['books[]']);
$comments = ($_POST['comments']);
}
else{
echo'<p>not submitted</p>';
}
//up until this point the code works fine
$query = 'INSERT INTO Student VALUES ($ID, $fname, $lname, $address, $city, $state, $zip, $phone, $email, $books, $comments)';
$success = $db_selected->query($query);
if($success){
$count = $db_selected->affectd_rows;
echo '<p>$count were added</p>';
}
else{
echo '<p>error</p>';
}
?>
I know that the information is being read from the html form correctly because I have checked by printing the individual variables. 我知道信息是从html表单正确读取的,因为我已经通过打印各个变量进行了检查。 I am not getting any error messages when I submit the form, just the "error" echo statement from the if/else statement, and no data is entered into the database. 提交表单时,没有收到任何错误消息,只是if / else语句中的“错误” echo语句,并且没有任何数据输入数据库。
I have also tried this: 我也尝试过这个:
if (!mysql_query($db_selected, $query)){
echo '<p>error</p>';
}
with the same results. 具有相同的结果。
Change this 改变这个
$query = 'INSERT INTO Student VALUES ($ID, $fname, $lname, $address, $city, $state, $zip, $phone, $email, $books, $comments)';
to 至
$query = "INSERT INTO Student VALUES ($ID, '$fname', '$lname', '$address', '$city', '$state', $zip, $phone, '$email', '$books', '$comments')";
I mean to say if its string then do like '$string' and also use 我的意思是说它的字符串是否喜欢'$ string'并使用
$db_selected->real_escape_string($stringval);
and use 和使用
echo $db_selected->error;
to check the error you got. 检查您得到的错误。
$ins="insert into Student (`id`,`fname`,`lname`,`address`,`city`,`state`,`zip`,`phone`,`email`,`books`,`comments`)values
('".$ID."','".$fname."','".$lname."','".$address."','".$city."','".$state."','".$zip."','".$phone."','".$email."','".$books."','".$comments."')";
mysql_query($ins);
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.