如何使用一条SQL语句从两个表中获取信息？

Question

I have to tables.

The first one (members) contains my customers id|name|email|key

The second (types) contains listings customer subscribes to id|customer_id|type|active

What I would like to do is to list all members that subscribed to a type of list. I can do this with 2 sql:s, but I guess there must be a better and faster way using som kind if JOIN maby and besides I get the wrong ORDER for my customers doing my way. I want ORDER by name.

<?
$type ='555';
$sql = mysql_query(" SELECT * FROM types WHERE type='$type' && active='1' ");
while($a = mysql_fetch_array($sql))
{
  $sql2 = mysql_query(" SELECT * FROM members WHERE id='{$a['customer_id']}' ");    
  while($b = mysql_fetch_array($sql2))
  {
    echo 'Name: '.$b['name'].'<br>';
  }
}
?>

Answer 1

 mysql_query(" SELECT * FROM types INNER JOIN members ON types.customer_id = members.id WHERE type='$type' AND active='1' ORDER by members.name ASC");

这应该为您解决问题

Answer 2

SELECT * FROM members 
JOIN types ON members.id = types.customer_id
WHERE types.type = ? AND types.active = '1'
ORDER BY members.name

Answer 3

perhaps this:

SELECT m.name, m.email 
    FROM members m left join types t 
    ON m.id=t.customer_id 
    WHERE t.type='$type' and t.active='1';