如何在Python列表的第一个位置添加元组

Question

I have a list that looks something like this

service = build('fusiontables', 'v1', developerKey=API_KEY)
query = "SELECT USStateCode, NOFU2008 FROM " + TABLE_ID
response = service.query().sql(sql=query).execute()
variables = {"data2008": json.encode(response['rows'])}
self.render_response('index.html', variables)

I am passing this to JavaScript and using this data to create an intensity map. However, the map requires the first tuple to be headers. So for that I need the data to do something like this:

var data = google.visualization.arrayToDataTable([
    ['State', 'No of Users'],
    ['US-PA', 200],
    ['US-CA', 300],
    ['US-NY', 400],
    ['US-TX', 500],
    ['US-SC', 600],
    ['US-MD', 700]
]);

How do I do this? Instead of these hardcoded values I want to use the actual data that I get from data2008. How do I add this to the first position?

Answer 1

To insert an object at the beginning of a list, you can use list.insert . The link is to the docs for mutable sequence methods, a list being a mutable sequence (as opposed to a str which is a sequence but not mutable)

data = [[u'US-AL', 290060.0], [u'US-AK', 46400.0], [u'US-AZ', 320320.0]]
data.insert(0,('State','No of users'))

Answer 2

您可以将其插入第一个位置：

my_list.insert(0, ('this', 'is', 'a', 'tuple'))

Answer 3

How to add a tuple to the first position of a list in Python?

Here's a list :

>>> my_list = list('abc')
>>> my_list
['a', 'b', 'c']

Insert a tuple at the beginning (index 0):

>>> my_list.insert(0, ())
>>> my_list
[(), 'a', 'b', 'c']