[英]Rails ActiveRecord sort by count of join table associations
I have a Resource
model that can be voted on using the "Acts As Votable" gem ( Github page ). 我有一个
Resource
模型,可以使用“Acts As Votable”gem( Github页面 )进行投票。 The voting system works perfectly but I am trying to display pages ordered by how many votes
each Resource
has. 投票系统运作完美,但我试图按每个
Resource
有多少votes
显示页面。
Currently my controller pulls Resources based on tags and aren't ordered: 目前我的控制器根据标签提取资源,并且没有订购:
@resources = Resource.where(language_id: "ruby")
If I take an individual resource and call "@resource.votes.size" it will return how many votes it has. 如果我获取一个单独的资源并调用“@ resource.votes.size”,它将返回它有多少票。 However, votes is another table so I think some sort of join needs to be done but I have not sure how to do it.
但是,投票是另一个表,所以我认为需要进行某种联接,但我不知道如何做。 What I need is a nice ordered
ActiveRecord
collection I can display like this? 我需要的是一个很好的有序
ActiveRecord
集合,我可以这样显示吗?
Book name - 19 votes
书名 - 19票
Book name - 15 votes
书名 - 15票
Book name - 9 votes
书名 - 9票
Book name - 8 votes
书名 - 8票
Try the following: 请尝试以下方法:
@resources = Resouce.select("resources.*, COUNT(votes.id) vote_count")
.joins(:votes)
.where(language_id: "ruby")
.group("resources.id")
.order("vote_count DESC")
@resources.each { |r| puts "#{r.whatever} #{r.vote_count}" }
To include resources with 0 votes, use an outer join. 要包含0票的资源,请使用外部联接。 If the example below doesn't work as is you'll have to alter the joins statement to join across the correct relations.
如果下面的示例不起作用,则必须更改连接语句以跨越正确的关系进行连接。
@resources = Resource.select("resources.*, COUNT(votes.id) vote_count")
.joins("LEFT OUTER JOIN votes ON votes.votable_id = resources.id AND votes.votable_type = 'Resource'")
.where(language_id: "ruby")
.group("resources.id")
.order("vote_count DESC")
Built-in support for left outer joins was introduced in Rails 5
so you can use that to do this. Rails 5
中引入了对左外连接的内置支持,因此您可以使用它来执行此操作。 This way you'll still keep the records that have 0 relationships: 这样您仍然可以保留具有0个关系的记录:
Resource
.where(language_id: 'ruby')
.left_joins(:votes)
.group(:id)
.select('resources.*', 'COUNT(votes.id) vote_count')
.order('vote_count DESC')
You need to apply Group clause like this: 你需要像这样应用Group子句 :
@resources = Resource.select('resources.*, count(votes.id) as votes_count').
joins(:votes).group(:id).order('votes_count DESC')
它将返回投票最多的资源
@resources.joins(:votes).group("resources.id").order("count(resources.id) DESC")
Probably the fastest and most painful way to handle it is to use counter cache: Here is a railscast - http://railscasts.com/episodes/23-counter-cache-column . 处理它的最快和最痛苦的方法可能是使用计数器缓存:这是一个railscast - http://railscasts.com/episodes/23-counter-cache-column 。
In short - you simply add a column called <association_name>_count
and add counter_cache: true
to you association definition. 简而言之 - 您只需添加一个名为
<association_name>_count
的列,并将counter_cache: true
添加到您的关联定义中。 Rails will take care of updating the <association_name>_count
column so it always shows the number of associated objects. Rails将负责更新
<association_name>_count
列,以便它始终显示关联对象的数量。
Warning: it will not pre-populate this column on creation, you need to do this in your migration for all existing parent records. 警告:它不会在创建时预先填充此列,您需要在迁移中为所有现有父记录执行此操作。
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