Java递归迷宫求解器问题
[英]Java Recursive Maze Solver problems
问题描述
I am trying to write a maze solver using recursion, and it seems that it tries each direction once, then stops and I can't figure out why. 
我正在尝试使用递归编写一个迷宫求解器，似乎它尝试了每个方向一次，然后停止并且我不知道为什么。 If you see a problem, please let me know. 如果您发现问题，请告诉我。 Key 0 is an open space 1 is a wall 2 is part of the path 3 is the end of the maze 钥匙0是一个开放空间1是墙壁2是路径的一部分3是迷宫的末端
public class Maze{
public static void main(String[] args){
int[][] maze =
{{1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1},
{0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,1},
{1,0,1,1,1,1,1,0,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,0,1,0,1,1,1,0,1,1,1,1,1,1,1,0,1,1,1,0,1,0,1},
{1,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,1,0,0,0,1,0,1,0,0,0,1,0,1,0,0,0,1,0,0,0,1,0,1,0,1},
{1,0,1,0,1,1,1,0,1,0,1,1,1,1,1,1,1,1,1,0,1,0,1,1,1,0,1,0,1,1,1,1,1,0,1,1,1,0,1,0,1,0,1,1,1,0,1,1,1,0,1},
{1,0,1,0,1,0,1,0,1,0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,1,0,1,0,1,0,0,0,0,0,1,0,0,0,1,0,1,0,0,0,0,0,1,0,0,0,1},
{1,0,1,1,1,0,1,0,1,1,1,0,1,0,1,0,1,0,1,1,1,1,1,0,1,0,1,0,1,1,1,0,1,1,1,0,1,1,1,0,1,1,1,1,1,1,1,0,1,0,1},
{1,0,0,0,0,0,1,0,0,0,0,0,1,0,1,0,1,0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,0,0,0,0,1,0,1},
{1,1,1,0,1,1,1,1,1,1,1,1,1,0,1,0,1,0,1,0,1,0,1,1,1,0,1,1,1,1,1,1,1,0,1,0,1,0,1,1,1,0,1,1,1,1,1,1,1,0,1},
{1,0,1,0,1,0,0,0,0,0,0,0,1,0,1,0,1,0,1,0,1,0,0,0,1,0,0,0,0,0,0,0,0,0,1,0,1,0,0,0,1,0,1,0,0,0,1,0,0,0,1},
{1,0,1,0,1,0,1,1,1,1,1,0,1,0,1,0,1,1,1,0,1,1,1,0,1,1,1,1,1,1,1,0,1,1,1,1,1,1,1,0,1,0,1,1,1,0,1,0,1,1,1},
{1,0,1,0,1,0,0,0,1,0,1,0,1,0,1,0,0,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,0,0,0,0,1,0,0,0,1,0,0,0,0,0,1},
{1,0,1,0,1,1,1,0,1,0,1,0,1,0,1,1,1,1,1,1,1,0,1,0,1,0,1,1,1,0,1,1,1,0,1,1,1,1,1,1,1,1,1,0,1,1,1,1,1,1,1},
{1,0,1,0,1,0,1,0,1,0,0,0,1,0,1,0,0,0,0,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,1},
{1,0,1,0,1,0,1,0,1,0,1,1,1,0,1,0,1,1,1,1,1,1,1,1,1,0,1,0,1,1,1,0,1,1,1,0,1,1,1,1,1,0,1,0,1,1,1,1,1,0,1},
{1,0,0,0,1,0,1,0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,1,0,0,0,1,0,0,0,1,0,1,0,0,0,1,0,1,0,0,0,1,0,1,0,0,0,0,0,1},
{1,0,1,1,1,0,1,0,1,1,1,1,1,1,1,0,1,0,1,1,1,1,1,0,1,1,1,1,1,0,1,0,1,0,1,1,1,0,1,0,1,1,1,1,1,0,1,1,1,0,1},
{1,0,0,0,0,0,1,0,0,0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,0,0,0,0,1,0,1,0,0,0,1,0,0,0,1,0,1,0,0,0,0,0,1,0,1,0,1},
{1,1,1,1,1,0,1,1,1,0,1,1,1,0,1,0,1,0,1,0,1,1,1,1,1,1,1,0,1,0,1,1,1,1,1,0,1,0,1,0,1,0,1,1,1,1,1,0,1,0,1},
{1,0,0,0,1,0,0,0,1,0,0,0,1,0,1,0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,0,0,1,0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,1},
{1,0,1,1,1,1,1,0,1,1,1,0,1,1,1,0,1,0,1,1,1,0,1,0,1,1,1,0,1,1,1,1,1,0,1,0,1,1,1,1,1,1,1,0,1,0,1,0,1,0,1},
{1,0,0,0,0,0,1,0,0,0,1,0,0,0,1,0,1,0,0,0,0,0,1,0,0,0,1,0,0,0,0,0,1,0,1,0,0,0,1,0,0,0,1,0,1,0,1,0,1,0,1},
{1,1,1,0,1,0,1,1,1,0,1,1,1,0,1,0,1,1,1,1,1,0,1,1,1,0,1,1,1,0,1,0,1,0,1,1,1,0,1,0,1,0,1,0,1,0,1,1,1,0,1},
{1,0,0,0,1,0,1,0,0,0,1,0,0,0,1,0,0,0,0,0,0,0,1,0,0,0,1,0,1,0,1,0,0,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,1},
{1,0,1,1,1,0,1,0,1,1,1,0,1,1,1,0,1,1,1,1,1,1,1,0,1,1,1,0,1,0,1,1,1,1,1,0,1,1,1,1,1,1,1,1,1,1,1,0,1,0,1},
{1,0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,1,0,0,0,1,0,1,0,0,0,1,0,0,0,0,0,1,0,0,0,0,0,0,0,1,0,1},
{1,0,1,1,1,1,1,1,1,0,1,1,1,0,1,1,1,0,1,0,1,0,1,0,1,0,1,1,1,0,1,0,1,0,1,1,1,1,1,0,1,0,1,1,1,0,1,0,1,0,1},
{1,0,0,0,0,0,0,0,1,0,1,0,1,0,1,0,0,0,1,0,1,0,1,0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,1,0,1,0,1,0,0,0,1,0,1,0,1},
{1,0,1,1,1,1,1,0,1,0,1,0,1,0,1,0,1,1,1,0,1,0,1,0,1,0,1,1,1,1,1,0,1,0,1,0,1,1,1,0,1,0,1,0,1,1,1,1,1,0,1},
{1,0,0,0,0,0,1,0,0,0,0,0,0,0,1,0,1,0,0,0,1,0,0,0,0,0,1,0,0,0,0,0,1,0,1,0,1,0,0,0,1,0,1,0,0,0,0,0,1,0,1},
{1,1,1,1,1,0,1,1,1,1,1,1,1,0,1,0,1,0,1,1,1,1,1,1,1,1,1,0,1,1,1,1,1,0,1,1,1,0,1,1,1,0,1,1,1,1,1,0,1,0,1},
{1,0,0,0,1,0,1,0,0,0,1,0,0,0,1,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,1,0,0,0,1,0,0,0,1,0,1,0,1},
{1,0,1,1,1,0,1,1,1,0,1,0,1,1,1,0,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,0,1,1,1,0,1,0,1,0,1,0,1},
{1,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,1,0,0,0,1},
{1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,0,1}};
boolean[][] posCheck = new boolean[maze.length][maze[0].length];
int r = 0;
int c = 0;
for(int row = 0; row < maze.length; row++){
for(int col = 0; col < maze[row].length; col++){
if(maze[row][col]==0){
r = row;
c = col;
}
}
}
maze[r][c] = 3;
mazeSolver(1, 0, 0, maze, posCheck);
}
public static boolean mazeSolver(int r, int c, int d, int[][]maze, boolean[][] posCheck){
maze[r][c] = 2;
if(maze[r][c] == 3){
print(maze);
return true;
}
if((c+1 < maze.length) && maze[r][c+1]==0 && d != 1 && !posCheck[r][c+1]){
if(d != 3)
posCheck[r][c+1] = true;
if(mazeSolver(r, c + 1, 3, maze, posCheck)){
maze[r][c] = 2;
return true;
}
}
if((r-1 >= 0) && maze[r-1][c]==0 && !posCheck[r-1][c] && d != 2){
if(d != 4)
posCheck[r-1][c] = true;
if(mazeSolver(r - 1, c, 4, maze, posCheck)){
maze[r][c] = 2;
return true;
}
}
if((c-1 >= 0) && maze[r][c-1]==0 && !posCheck[r][c-1] && d != 3){
if(d != 1)
posCheck[r][c-1] = true;
if(mazeSolver(r, c - 1, 1, maze, posCheck)){
maze[r][c] = 2;
return true;
}
}
if((r+1 < maze.length) && maze[r+1][c]==0 && !posCheck[r+1][c] && d != 4){
if(d != 2)
posCheck[r+1][c] = true;
if(mazeSolver(r + 1, c, 4, maze, posCheck)){
maze[r][c] = 2;
return true;
}
}
print(maze);
return false;
}
public static void print(int[][] maze){
for(int row = 0; row<maze.length; row++){
for(int col = 0; col<maze[row].length; col++)
System.out.print(maze[row][col]);
System.out.println();
}
}
}
2 个解决方案
解决方案1
5 2014-03-07 05:31:45
See you've already accepted an answer, but I'll add this in anyway... 看到您已经接受了答案，但是无论如何我都会添加它...
Recursion can be a really elegant way to solve some problems, but it can take a bit to get your head around. 递归可能是解决某些问题的一种非常优雅的方法，但要花点时间才能解决。 So this is not an exact answer to why your code doesn't work, but more of a higher level of how to use recursion in problems like this. 因此，这并不是您的代码为何无法正常工作的确切答案，而更多的是在诸如此类的问题中使用递归的更高层次。
Recursion problems generally have two parts to the data: some overall puzzle state, and some state associated with the current attempt. 递归问题通常包含两个部分：整体难题状态和与当前尝试相关的状态。 The whole recursion thing works because each time you call the recursive function you push some new state onto the call stack, and when the function exits it is removed for you, leaving you ready to try the next option. 整个递归过程都起作用，因为每次调用递归函数时，都会将一些新状态推入调用堆栈，并且当函数退出时，它将为您删除，因此您可以尝试使用下一个选项。 You can also manipulate the overall puzzle state within the recursive function, but generally when you're starting I'd suggest that any changes you make to the puzzle state in your function should be reverted when it exits. 您还可以在递归函数中操纵整体的拼图状态，但是通常在启动时，我建议您对函数中的拼图状态所做的任何更改都应在退出时恢复。
So in your case, the maze itself is puzzle state, the current path is a temporary change to the overall puzzle state, and the current position is transient state associated with the current call stack. 因此，在您的情况下，迷宫本身是拼图状态，当前路径是对整体拼图状态的临时更改，而当前位置是与当前调用堆栈关联的瞬态。
So the overall solution starts to take the form: 因此，整体解决方案开始采用以下形式：
// global state
private static int[][] maze;
private static boolean solve(int r, int c) {
// return true if I'm at the exit, false otherwise
}
and the main function simply provides the starting coords: 而main函数只是提供了起始坐标：
public static void main(String[] args) {
if (solve(1, 0)) {
print();
} else {
System.out.println("no solution found");
}
}
So the next step is the body of the "solve" function (I've set the exit position to 3 in the maze data - see the full solution at the end), which becomes: 因此，下一步是“解决”功能的主体（我已将迷宫数据中的出口位置设置为3-请参阅最后的完整解决方案），其变为：
private static boolean solve(int r, int c) {
if (maze[r][c] == 3) {
// we've found the exit
return true;
}
// push the current position onto the path
maze[r][c] == 2;
// try up / down / left / right - if any of these return true then we're done
if (available(r - 1, c) && solve(r - 1, c)) {
return true;
}
if (available(r + 1, c) && solve(r + 1, c)) {
return true;
}
if (available(r, c - 1) && solve(r, c - 1)) {
return true;
}
if (available(r, c + 1) && solve(r, c + 1)) {
return true;
}
// no result found from the current position so return false
// ... but have to revert the temporary state before doing so
maze[r][c] = 0;
return false;
}
This first checks the simple case of if we're at the exit, and returns true if that is the case. 首先检查是否在出口处的简单情况，如果是，则返回true。 If not, we push the current cell on to the path, and look for an available neighbour. 如果没有，我们将当前单元格推到路径上，并寻找可用的邻居。 If we find one we try each in turn, and this is the core of the recursion... If none of the available neighbours work then we've failed, and have to backtrack. 如果找到一个，我们将依次尝试每个，这是递归的核心...如果没有可用的邻居工作，则说明我们失败了，必须回溯。
Finally, if we're backtracking, we have to remove the current cell from the path. 最后，如果要回溯，则必须从路径中删除当前单元格。
And that's about it. 就是这样。 The 'available' function simply checks if the potential cell is in bounds and not a wall or already on the current path: “可用”功能仅检查潜在单元格是否在边界内，而不是在当前路径上是否在墙壁上：
private static boolean available(int r, int c) {
return r >= 0 && r < maze.length
&& c >= 0 && c < maze[r].length
&& (maze[r][c] == 0 || maze[r][c] == 3);
}
Full code: 完整代码：
public class Maze2 {
private static int[][] maze =
{{1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1},
{0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,1},
{1,0,1,1,1,1,1,0,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,0,1,0,1,1,1,0,1,1,1,1,1,1,1,0,1,1,1,0,1,0,1},
{1,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,1,0,0,0,1,0,1,0,0,0,1,0,1,0,0,0,1,0,0,0,1,0,1,0,1},
{1,0,1,0,1,1,1,0,1,0,1,1,1,1,1,1,1,1,1,0,1,0,1,1,1,0,1,0,1,1,1,1,1,0,1,1,1,0,1,0,1,0,1,1,1,0,1,1,1,0,1},
{1,0,1,0,1,0,1,0,1,0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,1,0,1,0,1,0,0,0,0,0,1,0,0,0,1,0,1,0,0,0,0,0,1,0,0,0,1},
{1,0,1,1,1,0,1,0,1,1,1,0,1,0,1,0,1,0,1,1,1,1,1,0,1,0,1,0,1,1,1,0,1,1,1,0,1,1,1,0,1,1,1,1,1,1,1,0,1,0,1},
{1,0,0,0,0,0,1,0,0,0,0,0,1,0,1,0,1,0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,0,0,0,0,1,0,1},
{1,1,1,0,1,1,1,1,1,1,1,1,1,0,1,0,1,0,1,0,1,0,1,1,1,0,1,1,1,1,1,1,1,0,1,0,1,0,1,1,1,0,1,1,1,1,1,1,1,0,1},
{1,0,1,0,1,0,0,0,0,0,0,0,1,0,1,0,1,0,1,0,1,0,0,0,1,0,0,0,0,0,0,0,0,0,1,0,1,0,0,0,1,0,1,0,0,0,1,0,0,0,1},
{1,0,1,0,1,0,1,1,1,1,1,0,1,0,1,0,1,1,1,0,1,1,1,0,1,1,1,1,1,1,1,0,1,1,1,1,1,1,1,0,1,0,1,1,1,0,1,0,1,1,1},
{1,0,1,0,1,0,0,0,1,0,1,0,1,0,1,0,0,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,0,0,0,0,1,0,0,0,1,0,0,0,0,0,1},
{1,0,1,0,1,1,1,0,1,0,1,0,1,0,1,1,1,1,1,1,1,0,1,0,1,0,1,1,1,0,1,1,1,0,1,1,1,1,1,1,1,1,1,0,1,1,1,1,1,1,1},
{1,0,1,0,1,0,1,0,1,0,0,0,1,0,1,0,0,0,0,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,1},
{1,0,1,0,1,0,1,0,1,0,1,1,1,0,1,0,1,1,1,1,1,1,1,1,1,0,1,0,1,1,1,0,1,1,1,0,1,1,1,1,1,0,1,0,1,1,1,1,1,0,1},
{1,0,0,0,1,0,1,0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,1,0,0,0,1,0,0,0,1,0,1,0,0,0,1,0,1,0,0,0,1,0,1,0,0,0,0,0,1},
{1,0,1,1,1,0,1,0,1,1,1,1,1,1,1,0,1,0,1,1,1,1,1,0,1,1,1,1,1,0,1,0,1,0,1,1,1,0,1,0,1,1,1,1,1,0,1,1,1,0,1},
{1,0,0,0,0,0,1,0,0,0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,0,0,0,0,1,0,1,0,0,0,1,0,0,0,1,0,1,0,0,0,0,0,1,0,1,0,1},
{1,1,1,1,1,0,1,1,1,0,1,1,1,0,1,0,1,0,1,0,1,1,1,1,1,1,1,0,1,0,1,1,1,1,1,0,1,0,1,0,1,0,1,1,1,1,1,0,1,0,1},
{1,0,0,0,1,0,0,0,1,0,0,0,1,0,1,0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,0,0,1,0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,1},
{1,0,1,1,1,1,1,0,1,1,1,0,1,1,1,0,1,0,1,1,1,0,1,0,1,1,1,0,1,1,1,1,1,0,1,0,1,1,1,1,1,1,1,0,1,0,1,0,1,0,1},
{1,0,0,0,0,0,1,0,0,0,1,0,0,0,1,0,1,0,0,0,0,0,1,0,0,0,1,0,0,0,0,0,1,0,1,0,0,0,1,0,0,0,1,0,1,0,1,0,1,0,1},
{1,1,1,0,1,0,1,1,1,0,1,1,1,0,1,0,1,1,1,1,1,0,1,1,1,0,1,1,1,0,1,0,1,0,1,1,1,0,1,0,1,0,1,0,1,0,1,1,1,0,1},
{1,0,0,0,1,0,1,0,0,0,1,0,0,0,1,0,0,0,0,0,0,0,1,0,0,0,1,0,1,0,1,0,0,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,1},
{1,0,1,1,1,0,1,0,1,1,1,0,1,1,1,0,1,1,1,1,1,1,1,0,1,1,1,0,1,0,1,1,1,1,1,0,1,1,1,1,1,1,1,1,1,1,1,0,1,0,1},
{1,0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,1,0,0,0,1,0,1,0,0,0,1,0,0,0,0,0,1,0,0,0,0,0,0,0,1,0,1},
{1,0,1,1,1,1,1,1,1,0,1,1,1,0,1,1,1,0,1,0,1,0,1,0,1,0,1,1,1,0,1,0,1,0,1,1,1,1,1,0,1,0,1,1,1,0,1,0,1,0,1},
{1,0,0,0,0,0,0,0,1,0,1,0,1,0,1,0,0,0,1,0,1,0,1,0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,1,0,1,0,1,0,0,0,1,0,1,0,1},
{1,0,1,1,1,1,1,0,1,0,1,0,1,0,1,0,1,1,1,0,1,0,1,0,1,0,1,1,1,1,1,0,1,0,1,0,1,1,1,0,1,0,1,0,1,1,1,1,1,0,1},
{1,0,0,0,0,0,1,0,0,0,0,0,0,0,1,0,1,0,0,0,1,0,0,0,0,0,1,0,0,0,0,0,1,0,1,0,1,0,0,0,1,0,1,0,0,0,0,0,1,0,1},
{1,1,1,1,1,0,1,1,1,1,1,1,1,0,1,0,1,0,1,1,1,1,1,1,1,1,1,0,1,1,1,1,1,0,1,1,1,0,1,1,1,0,1,1,1,1,1,0,1,0,1},
{1,0,0,0,1,0,1,0,0,0,1,0,0,0,1,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,1,0,0,0,1,0,0,0,1,0,1,0,1},
{1,0,1,1,1,0,1,1,1,0,1,0,1,1,1,0,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,0,1,1,1,0,1,0,1,0,1,0,1},
{1,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,1,0,0,0,1},
{1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,3,1}};
public static void main(String[] args) {
if (solve(1, 0)) {
print();
} else {
System.out.println("no solution found");
}
}
private static boolean solve(int r, int c) {
// if we're at the goal then we've solved it
if (maze[r][c] == 3) {
return true;
}
// mark the current cell as on the path
maze[r][c] = 2;
// try all available neighbours - if any of these return true then we're solved
if (available(r - 1, c) && solve(r - 1, c)) {
return true;
}
if (available(r + 1, c) && solve(r + 1, c)) {
return true;
}
if (available(r, c - 1) && solve(r, c - 1)) {
return true;
}
if (available(r, c + 1) && solve(r, c + 1)) {
return true;
}
// nothing found so remove the current cell from the path and backtrack
maze[r][c] = 0;
return false;
}
// cell is available if it is in the maze and either a clear space or the
// goal - it is not available if it is a wall or already on the current path
private static boolean available(int r, int c) {
return r >= 0 && r < maze.length
&& c >= 0 && c < maze[r].length
&& (maze[r][c] == 0 || maze[r][c] == 3);
}
// use symbols to make reading the output easier...
private static final char[] SYMBOLS = {' ', '#', '.', '*' };
private static void print(){
for(int row = 0; row < maze.length; ++row) {
for(int col = 0; col < maze[row].length; ++col) {
System.out.print(SYMBOLS[maze[row][col]]);
}
System.out.println();
}
}
}
Finally, if you want to print out all possible solutions instead of just the first one found, then just change the top of the solved function to: 最后，如果要打印出所有可能的解决方案，而不仅仅是找到的第一个解决方案，则只需将已解决函数的顶部更改为：
// if we're at the goal then print it but return false to continue searching
if (maze[r][c] == 3) {
print();
return false;
}
Happy recursing!!! 快乐递归！
解决方案2
3 已采纳 2014-03-07 03:56:25
You have asked four questions about this maze-recursion puzzle in the past five hours, which attests to how complicated it is. 在过去五个小时中，您已经问过有关此迷宫递归难题的四个问题，这证明它有多复杂。 This whole concept a 1/0 maze-grid has intrigued me, and I've come up with a class that should make it a whole lot simpler. 这整个概念的1/0迷宫电网已吸引了我，我想出了一个类，应该让一大堆简单。 If you're required to do recursion, then it will not be useful to you, but if you can use it, it eliminates much of its complexity. 如果需要进行递归，那么它将对您没有用，但是如果您可以使用它，那么它将消除很多复杂性。
There are two classes, and an Enum. 有两个类，一个枚举。
First, the enum, which defines the direction you want to move in the grid and determines the new indexes, one-at-a-time, based on its movement. 首先，枚举定义要在网格中移动的方向，并基于其移动一次确定新索引。
enum Direction {
UP(-1, 0),
DOWN(1, 0),
LEFT(0, -1),
RIGHT(0, 1);
private final int rowSteps;
private final int colSteps;
private Direction(int rowSteps, int colSteps) {
this.rowSteps = rowSteps;
this.colSteps = colSteps;
}
public int getNewRowIdx(int currentRowIdx) {
return (currentRowIdx + getRowSteps());
}
public int getNewColIdx(int currentColIdx) {
return (currentColIdx + getColSteps());
}
public int getRowSteps() {
return rowSteps;
}
public int getColSteps() {
return colSteps;
}
};
The main class is called MazePosition (below). 主要类称为MazePosition （下）。 First you set the maze-grid double-array into it, via its int[][] constructor, and store that instance statically: 首先，通过其int[][]构造函数在其中设置迷宫网格双数组，并静态存储该实例：
private static final MazePosition MAZE_HOLDER = new MazePosition(MAZE_GRID);
(This step could be designed better, but it works.) （可以将这一步骤设计得更好，但是可以。）
After setting the maze-grid (which is a one-time-only thing, per-execution), then the x/y constructor is used to declare an initial position: 设置迷宫网格（每次执行时，这是一次性的事情）后，然后使用x / y构造函数声明初始位置：
MazePosition pos = new MazePosition(0, 0);
And after that, just move as necessary: 然后，根据需要移动：
pos = pos.getNeighbor(Direction.RIGHT);
pos = pos.getNeighbor(Direction.RIGHT);
pos = pos.getNeighbor(Direction.DOWN);
...
The value of each position is retrieved by pos.getValue() or pos.isPath() --I think 1 is a "wall" and 0 is the "path". 每个位置的值由pos.getValue()或pos.isPath()检索-我认为1是“墙”， 0是“路径”。 (As an aside: The huge 2d-array should really contain one-bit booleans , instead of 4-byte ints , but looking at the array's code makes sense with int s, and doesn't with booleans... Note that it should at least be changed to byte s.) （顺便说一句：巨大的2d数组实际上应该包含一个booleans ，而不是4字节的ints ，但是查看数组的代码对int有意义，而对booleans则不行。请注意，它应该至少更改为byte s。）
So regarding movement, if you attempt to get a neighbor when there is none, such as moving left at the left edge, an IllegalStateException is thrown. 因此，关于移动，如果您尝试在没有邻居时获得邻居，例如在左边缘向左移动，则会引发IllegalStateException 。 Use the is*Edge() functions to avoid this. 使用is*Edge()函数可以避免这种情况。
The MazePosition class also has a convenient debugging function called getNineByNine() , which returns a 9x9 grid of the array values (as a string), where the middle item is the current position. MazePosition类还有一个方便的调试函数，称为getNineByNine() ，该函数返回9x9的数组值网格（作为字符串），其中中间项是当前位置。
import java.util.Arrays;
import java.util.Objects;
class MazePosition {
//state
private static int[][] MAZE_GRID;
private final int rowIdx;
private final int colIdx;
//internal
private final int rowIdxMinus1;
private final int colIdxMinus1;
public MazePosition(int[][] MAZE_GRID) {
if(this.MAZE_GRID != null) {
throw new IllegalStateException("Maze double-array already set. Use x/y constructor.");
}
MazePosition.MAZE_GRID = MAZE_GRID;
//TODO: Crash if null or empty, or sub-arrays null or empty, or unequal lengths, or contain anything but 0 or -1.
rowIdx = -1;
colIdx = -1;
rowIdxMinus1 = -1;
colIdxMinus1 = -1;
}
public MazePosition(int rowIdx, int colIdx) {
if(MazePosition.MAZE_GRID == null) {
throw new IllegalStateException("Must set maze double-array with: new MazePosition(int[][]).");
}
if(rowIdx < 0 || rowIdx >= MazePosition.getRowCount()) {
throw new IllegalArgumentException("rowIdx (" + rowIdx + ") is invalid.");
}
if(colIdx < 0 || colIdx >= MazePosition.getColumnCount()) {
throw new IllegalArgumentException("colIdx (" + colIdx + ") is invalid.");
}
this.rowIdx = rowIdx;
this.colIdx = colIdx;
rowIdxMinus1 = (rowIdx - 1);
colIdxMinus1 = (colIdx - 1);
}
public boolean isPath() {
return (getValue() == 0); //1???
}
public int getValue() {
return MazePosition.MAZE_GRID[getRowIdx()][getColumnIdx()];
}
public int getRowIdx() {
return rowIdx;
}
public int getColumnIdx() {
return colIdx;
}
public MazePosition getNeighbor(Direction dir) {
Objects.requireNonNull(dir, "dir");
return (new MazePosition(
dir.getNewRowIdx(getRowIdx()),
dir.getNewColIdx(getColumnIdx())));
}
public MazePosition getNeighborNullIfEdge(Direction dir) {
if(isEdgeForDirection(dir)) {
return null;
}
return getNeighbor(dir);
}
public int getNeighborValueNeg1IfEdge(Direction dir) {
MazePosition pos = getNeighborNullIfEdge(dir);
return ((pos == null) ? -1 : pos.getValue());
}
public static final int getRowCount() {
return MAZE_GRID.length;
}
public static final int getColumnCount() {
return MAZE_GRID[0].length;
}
public boolean isEdgeForDirection(Direction dir) {
Objects.requireNonNull(dir);
switch(dir) {
case UP: return isTopEdge();
case DOWN: return isBottomEdge();
case LEFT: return isLeftEdge();
case RIGHT: return isRightEdge();
}
throw new IllegalStateException(toString() + ", dir=" + dir);
}
public boolean isLeftEdge() {
return (getColumnIdx() == 0);
}
public boolean isTopEdge() {
return (getRowIdx() == 0);
}
public boolean isBottomEdge() {
return (getRowIdx() == rowIdxMinus1);
}
public boolean isRightEdge() {
return (getColumnIdx() == colIdxMinus1);
}
public String toString() {
return "[" + getRowIdx() + "," + getColumnIdx() + "]=" + getValue();
}
public String getNineByNine() {
int[][] nineByNine = new int[3][3];
//Middle row
nineByNine[1][1] = getValue();
nineByNine[1][0] = getNeighborValueNeg1IfEdge(Direction.LEFT);
nineByNine[1][2] = getNeighborValueNeg1IfEdge(Direction.RIGHT);
//Top
MazePosition posUp = getNeighborNullIfEdge(Direction.UP);
if(posUp != null) {
nineByNine[0][0] = posUp.getNeighborValueNeg1IfEdge(Direction.LEFT);
nineByNine[0][1] = posUp.getValue();
nineByNine[0][2] = posUp.getNeighborValueNeg1IfEdge(Direction.RIGHT);
}
//Bottom
MazePosition posDown = getNeighborNullIfEdge(Direction.DOWN);
if(posDown != null) {
nineByNine[2][0] = posDown.getNeighborValueNeg1IfEdge(Direction.LEFT);
nineByNine[2][1] = posDown.getValue();
nineByNine[2][2] = posDown.getNeighborValueNeg1IfEdge(Direction.RIGHT);
}
String sLS = System.getProperty("line.separator", "\r\n");
return "Middle position in 9x9 grid is *this*: " + toString() + sLS +
Arrays.toString(nineByNine[0]) + sLS +
Arrays.toString(nineByNine[1]) + sLS +
Arrays.toString(nineByNine[2]);
}
}
What this does not have, is "collision detection" or anything that actually figures out the maze-path for you. 它所没有的是“碰撞检测”或任何真正为您找到迷宫路径的东西。 It just moves throughout the grid, regardless if it's moving through walls or not. 它只是在整个网格中移动，无论它是否穿过墙壁。 There could easily be some getNeighborIfNotWall(Direction) and isWallToLeft() functions added, but I'll leave that to you. 可以很容易地添加一些getNeighborIfNotWall(Direction)和isWallToLeft()函数，但我将留给您。 ;) ;）
(Actually, these classes, without too much change, could be used to traverse any 2D array, although I'd probably add diagonal directions, such as UP_LEFT , and the ability to move multiple steps, such as getNeighbor(3, Direction.DOWN) ). （实际上，这些类无需进行太多更改，就可以用于遍历任何2D数组，尽管我可能会添加对角线方向（例如UP_LEFT ）以及移动多个步骤的能力，例如getNeighbor(3, Direction.DOWN) ）。
Here's a demo usage: 这是一个演示用法：
public class MazePosDemo {
private static final int[][] MAZE_GRID = new int[][] {
//mega maze grid goes here...
};
private static final MazePosition MAZE_HOLDER = new MazePosition(MAZE_GRID);
public static final void main(String[] ignored) {
MazePosition pos = new MazePosition(0, 0);
System.out.println("start: " + pos);
pos = pos.getNeighbor(Direction.RIGHT);
System.out.println("right: " + pos);
pos = pos.getNeighbor(Direction.RIGHT);
System.out.println("right: " + pos);
pos = pos.getNeighbor(Direction.DOWN);
System.out.println("down: " + pos);
pos = pos.getNeighbor(Direction.DOWN);
System.out.println("down: " + pos);
pos = pos.getNeighbor(Direction.RIGHT);
System.out.println("right: " + pos);
pos = pos.getNeighbor(Direction.DOWN);
System.out.println("down: " + pos);
pos = pos.getNeighbor(Direction.LEFT);
System.out.println("left: " + pos);
pos = pos.getNeighbor(Direction.UP);
System.out.println("up: " + pos);
pos = pos.getNeighbor(Direction.UP);
System.out.println("up: " + pos);
System.out.println(pos.getNineByNine());
}
}
Output 输出量
[C:\java_code\]java MazePosDemo
start: [0,0]=1
right: [0,1]=1
right: [0,2]=1
down: [1,2]=1
down: [2,2]=1
right: [2,3]=1
down: [3,3]=0
left: [3,2]=1
up: [2,2]=1
up: [1,2]=1
Middle position in 9x9 grid is *this*: [1,2]=1
[1, 1, 1]
[0, 1, 0]
[0, 1, 1]
And here's the entire source-code file, containing all of the above (including the mega-maze-array): 这是完整的源代码文件，其中包含上述所有内容（包括mega-maze-array）：
//Needed only by MazePosition
import java.util.Arrays;
import java.util.Objects;
enum Direction {
UP(-1, 0),
DOWN(1, 0),
LEFT(0, -1),
RIGHT(0, 1);
//config
private final int rowSteps;
private final int colSteps;
private Direction(int rowSteps, int colSteps) {
this.rowSteps = rowSteps;
this.colSteps = colSteps;
}
public int getNewRowIdx(int currentRowIdx) {
return (currentRowIdx + getRowSteps());
}
public int getNewColIdx(int currentColIdx) {
return (currentColIdx + getColSteps());
}
public int getRowSteps() {
return rowSteps;
}
public int getColSteps() {
return colSteps;
}
};
class MazePosition {
//config
private static int[][] MAZE_GRID;
private final int rowIdx;
private final int colIdx;
//internal
private final int rowIdxMinus1;
private final int colIdxMinus1;
public MazePosition(int[][] MAZE_GRID) {
if(this.MAZE_GRID != null) {
throw new IllegalStateException("Maze double-array already set. Use x/y constructor.");
}
MazePosition.MAZE_GRID = MAZE_GRID;
//TODO: Crash if null or empty, or sub-arrays null or empty, or unequal lengths, or contain anything but 0 or -1.
rowIdx = -1;
colIdx = -1;
rowIdxMinus1 = -1;
colIdxMinus1 = -1;
}
public MazePosition(int rowIdx, int colIdx) {
if(MazePosition.MAZE_GRID == null) {
throw new IllegalStateException("Must set maze double-array with: new MazePosition(int[][]).");
}
if(rowIdx < 0 || rowIdx >= MazePosition.getRowCount()) {
throw new IllegalArgumentException("rowIdx (" + rowIdx + ") is invalid.");
}
if(colIdx < 0 || colIdx >= MazePosition.getColumnCount()) {
throw new IllegalArgumentException("colIdx (" + colIdx + ") is invalid.");
}
this.rowIdx = rowIdx;
this.colIdx = colIdx;
rowIdxMinus1 = (rowIdx - 1);
colIdxMinus1 = (colIdx - 1);
}
public boolean isPath() {
return (getValue() == 0); //1???
}
public int getValue() {
return MazePosition.MAZE_GRID[getRowIdx()][getColumnIdx()];
}
public int getRowIdx() {
return rowIdx;
}
public int getColumnIdx() {
return colIdx;
}
public MazePosition getNeighbor(Direction dir) {
Objects.requireNonNull(dir, "dir");
return (new MazePosition(
dir.getNewRowIdx(getRowIdx()),
dir.getNewColIdx(getColumnIdx())));
}
public MazePosition getNeighborNullIfEdge(Direction dir) {
if(isEdgeForDirection(dir)) {
return null;
}
return getNeighbor(dir);
}
public int getNeighborValueNeg1IfEdge(Direction dir) {
MazePosition pos = getNeighborNullIfEdge(dir);
return ((pos == null) ? -1 : pos.getValue());
}
public static final int getRowCount() {
return MAZE_GRID.length;
}
public static final int getColumnCount() {
return MAZE_GRID[0].length;
}
public boolean isEdgeForDirection(Direction dir) {
Objects.requireNonNull(dir);
switch(dir) {
case UP: return isTopEdge();
case DOWN: return isBottomEdge();
case LEFT: return isLeftEdge();
case RIGHT: return isRightEdge();
}
throw new IllegalStateException(toString() + ", dir=" + dir);
}
public boolean isLeftEdge() {
return (getColumnIdx() == 0);
}
public boolean isTopEdge() {
return (getRowIdx() == 0);
}
public boolean isBottomEdge() {
return (getRowIdx() == rowIdxMinus1);
}
public boolean isRightEdge() {
return (getColumnIdx() == colIdxMinus1);
}
public String toString() {
return "[" + getRowIdx() + "," + getColumnIdx() + "]=" + getValue();
}
public String getNineByNine() {
int[][] nineByNine = new int[3][3];
//Middle row
nineByNine[1][1] = getValue();
nineByNine[1][0] = getNeighborValueNeg1IfEdge(Direction.LEFT);
nineByNine[1][2] = getNeighborValueNeg1IfEdge(Direction.RIGHT);
//Top
MazePosition posUp = getNeighborNullIfEdge(Direction.UP);
if(posUp != null) {
nineByNine[0][0] = posUp.getNeighborValueNeg1IfEdge(Direction.LEFT);
nineByNine[0][1] = posUp.getValue();
nineByNine[0][2] = posUp.getNeighborValueNeg1IfEdge(Direction.RIGHT);
}
//Bottom
MazePosition posDown = getNeighborNullIfEdge(Direction.DOWN);
if(posDown != null) {
nineByNine[2][0] = posDown.getNeighborValueNeg1IfEdge(Direction.LEFT);
nineByNine[2][1] = posDown.getValue();
nineByNine[2][2] = posDown.getNeighborValueNeg1IfEdge(Direction.RIGHT);
}
String sLS = System.getProperty("line.separator", "\r\n");
return "Middle position in 9x9 grid is *this*: " + toString() + sLS +
Arrays.toString(nineByNine[0]) + sLS +
Arrays.toString(nineByNine[1]) + sLS +
Arrays.toString(nineByNine[2]);
}
}
public class MazePosDemo {
private static final int[][] MAZE_GRID = new int[][] {
{1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1},
{0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,1},
{1,0,1,1,1,1,1,0,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,0,1,0,1,1,1,0,1,1,1,1,1,1,1,0,1,1,1,0,1,0,1},
{1,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,1,0,0,0,1,0,1,0,0,0,1,0,1,0,0,0,1,0,0,0,1,0,1,0,1},
{1,0,1,0,1,1,1,0,1,0,1,1,1,1,1,1,1,1,1,0,1,0,1,1,1,0,1,0,1,1,1,1,1,0,1,1,1,0,1,0,1,0,1,1,1,0,1,1,1,0,1},
{1,0,1,0,1,0,1,0,1,0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,1,0,1,0,1,0,0,0,0,0,1,0,0,0,1,0,1,0,0,0,0,0,1,0,0,0,1},
{1,0,1,1,1,0,1,0,1,1,1,0,1,0,1,0,1,0,1,1,1,1,1,0,1,0,1,0,1,1,1,0,1,1,1,0,1,1,1,0,1,1,1,1,1,1,1,0,1,0,1},
{1,0,0,0,0,0,1,0,0,0,0,0,1,0,1,0,1,0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,0,0,0,0,1,0,1},
{1,1,1,0,1,1,1,1,1,1,1,1,1,0,1,0,1,0,1,0,1,0,1,1,1,0,1,1,1,1,1,1,1,0,1,0,1,0,1,1,1,0,1,1,1,1,1,1,1,0,1},
{1,0,1,0,1,0,0,0,0,0,0,0,1,0,1,0,1,0,1,0,1,0,0,0,1,0,0,0,0,0,0,0,0,0,1,0,1,0,0,0,1,0,1,0,0,0,1,0,0,0,1},
{1,0,1,0,1,0,1,1,1,1,1,0,1,0,1,0,1,1,1,0,1,1,1,0,1,1,1,1,1,1,1,0,1,1,1,1,1,1,1,0,1,0,1,1,1,0,1,0,1,1,1},
{1,0,1,0,1,0,0,0,1,0,1,0,1,0,1,0,0,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,0,0,0,0,1,0,0,0,1,0,0,0,0,0,1},
{1,0,1,0,1,1,1,0,1,0,1,0,1,0,1,1,1,1,1,1,1,0,1,0,1,0,1,1,1,0,1,1,1,0,1,1,1,1,1,1,1,1,1,0,1,1,1,1,1,1,1},
{1,0,1,0,1,0,1,0,1,0,0,0,1,0,1,0,0,0,0,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,1},
{1,0,1,0,1,0,1,0,1,0,1,1,1,0,1,0,1,1,1,1,1,1,1,1,1,0,1,0,1,1,1,0,1,1,1,0,1,1,1,1,1,0,1,0,1,1,1,1,1,0,1},
{1,0,0,0,1,0,1,0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,1,0,0,0,1,0,0,0,1,0,1,0,0,0,1,0,1,0,0,0,1,0,1,0,0,0,0,0,1},
{1,0,1,1,1,0,1,0,1,1,1,1,1,1,1,0,1,0,1,1,1,1,1,0,1,1,1,1,1,0,1,0,1,0,1,1,1,0,1,0,1,1,1,1,1,0,1,1,1,0,1},
{1,0,0,0,0,0,1,0,0,0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,0,0,0,0,1,0,1,0,0,0,1,0,0,0,1,0,1,0,0,0,0,0,1,0,1,0,1},
{1,1,1,1,1,0,1,1,1,0,1,1,1,0,1,0,1,0,1,0,1,1,1,1,1,1,1,0,1,0,1,1,1,1,1,0,1,0,1,0,1,0,1,1,1,1,1,0,1,0,1},
{1,0,0,0,1,0,0,0,1,0,0,0,1,0,1,0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,0,0,1,0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,1},
{1,0,1,1,1,1,1,0,1,1,1,0,1,1,1,0,1,0,1,1,1,0,1,0,1,1,1,0,1,1,1,1,1,0,1,0,1,1,1,1,1,1,1,0,1,0,1,0,1,0,1},
{1,0,0,0,0,0,1,0,0,0,1,0,0,0,1,0,1,0,0,0,0,0,1,0,0,0,1,0,0,0,0,0,1,0,1,0,0,0,1,0,0,0,1,0,1,0,1,0,1,0,1},
{1,1,1,0,1,0,1,1,1,0,1,1,1,0,1,0,1,1,1,1,1,0,1,1,1,0,1,1,1,0,1,0,1,0,1,1,1,0,1,0,1,0,1,0,1,0,1,1,1,0,1},
{1,0,0,0,1,0,1,0,0,0,1,0,0,0,1,0,0,0,0,0,0,0,1,0,0,0,1,0,1,0,1,0,0,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,1},
{1,0,1,1,1,0,1,0,1,1,1,0,1,1,1,0,1,1,1,1,1,1,1,0,1,1,1,0,1,0,1,1,1,1,1,0,1,1,1,1,1,1,1,1,1,1,1,0,1,0,1},
{1,0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,1,0,0,0,1,0,1,0,0,0,1,0,0,0,0,0,1,0,0,0,0,0,0,0,1,0,1},
{1,0,1,1,1,1,1,1,1,0,1,1,1,0,1,1,1,0,1,0,1,0,1,0,1,0,1,1,1,0,1,0,1,0,1,1,1,1,1,0,1,0,1,1,1,0,1,0,1,0,1},
{1,0,0,0,0,0,0,0,1,0,1,0,1,0,1,0,0,0,1,0,1,0,1,0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,1,0,1,0,1,0,0,0,1,0,1,0,1},
{1,0,1,1,1,1,1,0,1,0,1,0,1,0,1,0,1,1,1,0,1,0,1,0,1,0,1,1,1,1,1,0,1,0,1,0,1,1,1,0,1,0,1,0,1,1,1,1,1,0,1},
{1,0,0,0,0,0,1,0,0,0,0,0,0,0,1,0,1,0,0,0,1,0,0,0,0,0,1,0,0,0,0,0,1,0,1,0,1,0,0,0,1,0,1,0,0,0,0,0,1,0,1},
{1,1,1,1,1,0,1,1,1,1,1,1,1,0,1,0,1,0,1,1,1,1,1,1,1,1,1,0,1,1,1,1,1,0,1,1,1,0,1,1,1,0,1,1,1,1,1,0,1,0,1},
{1,0,0,0,1,0,1,0,0,0,1,0,0,0,1,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,1,0,0,0,1,0,0,0,1,0,1,0,1},
{1,0,1,1,1,0,1,1,1,0,1,0,1,1,1,0,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,0,1,1,1,0,1,0,1,0,1,0,1},
{1,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,1,0,0,0,1},
{1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,0,1}};
private static final MazePosition MAZE_HOLDER = new MazePosition(MAZE_GRID);
public static final void main(String[] ignored) {
MazePosition pos = new MazePosition(0, 0);
System.out.println("start: " + pos);
pos = pos.getNeighbor(Direction.RIGHT);
System.out.println("right: " + pos);
pos = pos.getNeighbor(Direction.RIGHT);
System.out.println("right: " + pos);
pos = pos.getNeighbor(Direction.DOWN);
System.out.println("down: " + pos);
pos = pos.getNeighbor(Direction.DOWN);
System.out.println("down: " + pos);
pos = pos.getNeighbor(Direction.RIGHT);
System.out.println("right: " + pos);
pos = pos.getNeighbor(Direction.DOWN);
System.out.println("down: " + pos);
pos = pos.getNeighbor(Direction.LEFT);
System.out.println("left: " + pos);
pos = pos.getNeighbor(Direction.UP);
System.out.println("up: " + pos);
pos = pos.getNeighbor(Direction.UP);
System.out.println("up: " + pos);
System.out.println(pos.getNineByNine());
}
}
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