使用glob和os将文件放入文件夹并重命名？

Question

I have a huge folder what contains about 5000 files with names similar to:

Rop OE[1932].exo
Make Dat[1932].edd
Back W'E[1934].exl
Pack Trees Pop[1944].exl
R.P END[1962].exl
Original CL0[1998].exp

I want it to create folders for all of these files with the name from the file above (without the extension) as seen below

Rop OE[1932]
Make Dat[1932]
Back W'E[1934]
Pack Trees Pop[1944]
R.P END[1962]
Original CL0[1998]

Then rename all of the files to remove the what appears to be a year so they appear as below

Rop OE.exo
Make Dat.edd
Back W'E.exl
Pack Trees Pop.exl
R.P END.exl
Original CL0.exp

And then all of the files to be put in their associating folder (same name)

What's the best way to do this, I've attempted to use glob to get the list and cycle through them all but it didn't seem to work correct.

Answer 1

Use the glob , os , shutil and re libs:

import glob
import shutil
import os
import re

root = 'path/to/folder/*'

for f in glob.glob(root):
    dirname = f.rsplit('.')[0]
    os.mkdir(dirname)
    filename = os.path.split(re.sub(r'\[\d+\]', '', f))[-1]
    shutil.move(f, os.path.join(dirname, filename))