[英]Starting application context without a main class
I am using a scheduler with Spring technology using Quartz. 我正在使用Quartz的Spring技术调度程序。
Is it possible to launch my context without creating a main class? 是否可以在不创建主类的情况下启动我的上下文? Not using the following example:
不使用以下示例:
import org.springframework.context.support.ClassPathXmlApplicationContext;
public class App
{
public static void main( String[] args ) throws Exception
{
new ClassPathXmlApplicationContext("Spring-Quartz.xml");
}
}
For example I want my Context to be configured when I launch my jetty server. 例如,我希望在启动jetty服务器时配置我的Context。
If you launch your spring application on an application server, you can use a listener inside of the web.xml to start your spring container. 如果在应用程序服务器上启动spring应用程序,则可以使用web.xml内部的侦听器来启动spring容器。
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath*:context.xml</param-value>
</context-param>
Another example: If you want to use spring in a blueprint OSGi environment, the blueprint extender starts all contexts in META-INF/spring or OSGI-INF/blueprint for you. 另一个例子:如果你想在蓝图OSGi环境中使用spring,蓝图扩展器会为你启动META-INF / spring或OSGI-INF / blueprint中的所有上下文。
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