在 R 中删除包含特定字符串的行

Question

I would like to exclude lines containing a string "REVERSE", but my lines do not match exactly with the word, just contain it.

My input data frame:

   Value   Name 
    55     REVERSE223   
    22     GENJJS
    33     REVERSE456
    44     GENJKI

My expected output:

   Value   Name 
    22     GENJJS
    44     GENJKI

Answer 1

This should do the trick:

df[- grep("REVERSE", df$Name),]

Or a safer version would be:

df[!grepl("REVERSE", df$Name),]

Answer 2

You could use dplyr::filter() and negate a grepl() match:

library(dplyr)

df %>% 
  filter(!grepl('REVERSE', Name))

Or with dplyr::filter() and negating a stringr::str_detect() match:

library(stringr)

df %>% 
  filter(!str_detect(Name, 'REVERSE'))

Answer 3

Actually I would use:

df[ grep("REVERSE", df$Name, invert = TRUE) , ]

This will avoid deleting all of the records if the desired search word is not contained in any of the rows.

Answer 4

You can use stri_detect_fixed function from stringi package

stri_detect_fixed(c("REVERSE223","GENJJS"),"REVERSE")
[1]  TRUE FALSE

Answer 5

如果它是多个字符串，则可以使用此函数df[!grepl("REVERSE|GENJJS", df$Name),]

Answer 6

You can use it in the same datafram (df) using the previously provided code

df[!grepl("REVERSE", df$Name),]

or you might assign a different name to the datafram using this code

df1<-df[!grepl("REVERSE", df$Name),]

Answer 7

A late answer building on BobD59's and hidden-layer's responses.

This removes multiple specific strings, whilst avoiding deleting all of the records if the desired search word is not contained in any of the rows.

df1 <-
   df[!grepl("REVERSE|GENJJS", df$Name), (invert = TRUE), ]