通过网络访问Web服务

Question

I created an asp.net web service and using emulator I can easily access to the web service what I want now that I want to access to the web service via network so my phone will be the client and my laptop will be server trying to do that for many hours but nothing happened still gave me java.lang.NullPointerException . I created a local network and see the picture to see the network information http://s9.postimg.org/k3a7t754f/image.png and when I connected to the network my IP address in the phone is 192.168.173.205

• this is my first class UserService this class will call the

   package com.routingware.services; import android.util.Log; import com.routingware.database.models.User; import org.ksoap2.SoapEnvelope; import org.ksoap2.serialization.PropertyInfo; import org.ksoap2.serialization.SoapObject; import org.ksoap2.serialization.SoapSerializationEnvelope; import org.ksoap2.transport.HttpTransportSE; public String NAMESPACE = "http://tempuri.org/"; public String METHOD = ""; public String ACTION = ""; public String URL = "http://192.168.173.1/projectnetwork/"; public class UserService extends CommonClass { public UserService (String MethodName, String PageName) { METHOD = MethodName; ACTION = NAMESPACE + MethodName; URL = URL + PageName; } public User CheckLogin (String Username, String Password) { User user = null; SoapObject Request = new SoapObject(NAMESPACE, METHOD); // Send Username as parameter PropertyInfo Pi = new PropertyInfo(); Pi.setName("Username"); Pi.setValue(Username); Pi.setType(String.class); Request.addProperty(Pi); // Send Password as parameter Pi = new PropertyInfo(); Pi.setName("Password"); Pi.setValue(Password); Pi.setType(String.class); Request.addProperty(Pi); SoapSerializationEnvelope envelope = new SoapSerializationEnvelope( SoapEnvelope.VER11); envelope.dotNet = true; envelope.setOutputSoapObject(Request); envelope.implicitTypes = true; envelope.addMapping(NAMESPACE, "User",new User().getClass()); HttpTransportSE httpTransport = new HttpTransportSE(URL); httpTransport.debug = true; try { Log.e("call","1"); httpTransport.call(ACTION, envelope); SoapObject Response = (SoapObject)envelope.getResponse(); user = new User(); user.setUserID(Integer.parseInt(Response.getProperty(0).toString())); user.setUserName(Response.getProperty(1).toString()); user.setUserPasswrd(Response.getProperty(2).toString()); user.setBranchID(Integer.parseInt(Response.getProperty(3).toString())); user.setCompanyID(Integer.parseInt(Response.getProperty(4).toString())); user.setUserState(Boolean.parseBoolean(Response.getProperty(5).toString())); } catch (Exception ex) { Log.e("call",ex.toString()); return null; } finally { return user; } } } 

• call method from AsyncTaskclass

   @Override protected User doInBackground(Void... params) { try { return new UserService("CheckFirstTimeLogin", "UserApi.asmx") .CheckLogin(mUsername, mPassword); } catch (Exception e) { return null; } } @Override protected void onPreExecute() { super.onPreExecute(); alertDialog = new AlertDialog.Builder(LoginActivity.this).create(); } @Override protected void onPostExecute(User user) { if (user == null) { onCancelled(); alertDialog.setTitle(R.string.login_connecnt_title); alertDialog.setMessage("خطأ اثناء عملية الإتصال"); alertDialog.show(); } } 

sorry for my bad english

Answer 1

Can you post the logs?. Is your device connected to the same wifi network your laptop is connected. Snce you are using local network as your service, the device should be connected to the same wifi network.

Answer 2

问题是ksoap2使用http的端口为80，所以我要防火墙并使其对其他设备开放，我按照此处的步骤操作http://www.thewindowsclub.com/block-open-port-windows-8 -防火墙