检查号码是否在号码列表中

Question

I am new to programming and I am trying to figure out how to create a list of numbers like so (5, 10, 15, 20, 25, all the way to 500) then be able to check if a player score is equal to any of these numbers.

My code so far is this.. It works, but only if the score is 5.

private void drawPower() {

    if (myWorld.getScore() == 5) {
        batcher.draw(Power, pipe3.getX(), pipe3.getY() + pipe3.getHeight()
                + 30, 20, -14);

    }

}

I need to know what needs to be done so instead of

if (myWorld.getScore() == 5) {

it would be

if (myWorld.getScore() == "any number in the list") {

Answer 1

I wouldn't use an array of multiples of 5 from 5 to 100.

I would just check if it's a multiple of 5 and if it's between 5 and 500 .

int score = myWorld.getScore();
if (score >= 5 && score <= 500 && score % 5 == 0) {

Answer 2

@rgettman's answer is definitely the best way. However to answer the question more generally (as it may come up again):

if(Arrays.asList(5, 10, 15, 20).contains(myWorld.getScore()))

However, if the numbers have any sort of pattern to them, a solution like rgettman's is definitely better. This is if the numbers are more or less arbitrary.

Answer 3

Since the array contains all the numbers from 5 up to 500 (with a step of 5) then:

public hasScore(int score) {  
   int position = (score/5) - 1;  
   return arrray[position] == score;  
}  

Ie the score should be in position (i/5) - 1 (since 5 in index 0, 10 in index 1) and so on.
So check if the score is indeed in the expected location it should be