MySQL WHERE子句 - 年龄大于/小于

Question

I have the following SELECT that I can't get to work:

SELECT COUNT(userid) FROM login 
WHERE 17 < YEAR(DATE_SUB(NOW(), INTERVAL TO_DAYS(profile_birthdate) DAY) 
AND 46 > YEAR(DATE_SUB(NOW(), INTERVAL TO_DAYS(profile_birthdate) DAY);

The following works fine so I know the YEAR equation is sound:

SELECT YEAR(DATE_SUB(NOW(), INTERVAL TO_DAYS(profile_birthdate) DAY)) 
AS age FROM login;

Just wondering how to get the top one to work; also, is there a similar way then repeating the YEAR equation twice?

thankyou

Answer 1

It is just typo. You have missed close brackets.

SELECT COUNT(userid) FROM login 
WHERE 17 < YEAR(DATE_SUB(NOW(), INTERVAL TO_DAYS(profile_birthdate) DAY)) 
    AND 46 > YEAR(DATE_SUB(NOW(), INTERVAL TO_DAYS(profile_birthdate) DAY));

Answer 2

You can try BETWEEN in this Query and don't forget the the missing close ")"

SELECT COUNT(userid) FROM login 
WHERE YEAR(DATE_SUB(NOW(), INTERVAL TO_DAYS(profile_birthdate) DAY)) BETWEEN 17 AND 46