[英]How to read in csv file to array in bash script
I have written the following code to read in my csv file (which has a fixed number of columns but not a fixed number of rows) into my script as an array. 我编写了以下代码,以将我的csv文件(具有固定的列数但没有固定的行数)作为数组读入脚本。 I need it to be a shell script. 我需要它是一个shell脚本。
usernames x1 x2 x3 x4
username1, 5 5 4 2
username2, 6 3 2 0
username3, 8 4 9 3
My code 我的密码
#!/bin/bash
set oldIFS = $IFS
set IFS=,
read -a line < something.csv
another option I have used is 我使用的另一个选择是
#!/bin/bash
while IFS=$'\t' reaad -r -a line
do
echo $line
done < something.csv
for both I tried some test code to see what the size of the array line would be and I seem to be getting a size of 10 with the first one but the array only outputs username. 对于这两者,我尝试了一些测试代码来查看数组行的大小,并且第一个似乎是10,但是数组仅输出用户名。 For the second one, I seem to be getting a size of 0 but the array outputs the whole csv. 对于第二个,我似乎得到的大小为0,但数组输出整个csv。
Help is much appreciated! 非常感谢帮助!
You may consider using AWK
with a regular expression in FS
variable like this: 您可以考虑将AWK
与FS
变量中的正则表达式一起使用,如下所示:
awk 'BEGIN { FS=",?[ \t]*"; } { print $1,"|",$2,"|",$3,"|",$4,"|",$5; }'
or this 或这个
awk 'BEGIN { FS=",?[ \t]*"; OFS="|"; } { $1=$1; print $0; }'
( $1=$1
is required to rebuild $0 with new OFS) (需要$1=$1
才能用新的OFS重建$ 0)
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