在不了解字符串的情况下使用struct.unpack（）

Question

I need to parse a big-endian binary file and convert it to little-endian. However, the people who have handed the file over to me seem unable to tell me anything about what data types it contains, or how it is organized — the only thing they know for certain is that it is a big-endian binary file with some old data. The function struct.unpack(), however, requires a format character as its first argument.

This is the first line of the binary file:

import binascii
path = "BC2003_lr_m32_chab_Im.ised"            
with open(path, 'rb') as fd:
    line = fd.readline()
    print binascii.hexlify(line)

a0040000dd0000000000000080e2f54780f1094840c61a4800a92d48c0d9424840a05a48404d7548e09d8948a0689a48e03fad48a063c248c01bda48c0b8f448804a0949100b1a49e0d62c49e0ed41499097594900247449a0a57f4900d98549b0278c49a0c2924990ad9949a0eba049e080a8490072b049c0c2b849d077c1493096ca494022d449a021de49a099e849e08ff349500a

Is it possible to change the endianness of a file without knowing anything about it?

Answer 1

You cannot do this without knowing the datatypes. There is little point in attempting to do so otherwise.

Even if it was a homogeneous sequence of one datatype, you'd still need to know what you are dealing with; flipping the byte order in double values is very different from short integers.

Take a look at the formatting characters table ; anything with a different byte size in it will result in a different set of bytes being swapped; for double values, you need to reverse the order of every 8 bytes, for example.

If you know what data should be in the file, then at least you have a starting point; you'd have to puzzle out how those values fit into the bytes given. It'll be a puzzle, but with a target set of values you can build a map of the datatypes contained, then write a byte-order adjustment script. If you don't even have that, best not to start as the task is impossible to achieve.