如何将表单数据插入mysql数据库

Question

I'm trying to insert the data that's in the form into the database that I made. I keep getting this error when I check if the data is in the database:

Error Code: 1064. You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'user_comments' at line 1

This is my php:

<?php
$db_connection = mysqli_connect('localhost','root','',"project_online_planner");
if (!$db_connection){
    die('Failed to connect to MySql:'.mysql_error());
}else{
    echo "it worked";
}

if(isset($_POST['insertComments'])){
    $name=$_POST['name'];
    $comment=$_POST['comment'];
    mysqli_query($db_connection,"INSERT INTO user_comments (name, comment) VALUES ($name, $comment)");
    Print "Your information has been successfully added to the database.";
}

?>

This is my html:

<div id="uploadComments">
    <form id="insertComments" name="insertComments" method="post">
        <label for="name">Name: </label><input type="text" id="name" name="name"><br/>
        <label for="comment">Comments: </label><textarea name="comment" id="comment"></textarea>
        <input type="submit" value="Submit">
    </form>
</div>

Answer 1

As pervious people have commented you should construct your "query" separately, makes it easier to handle and change. Additionally when passing any variable into your query you need to bring them out of the string so PHP can process them correctly.

Here is how I would suggest you structure your code:

....

$name=$_POST['name'];
$comment=$_POST['comment'];

$sql="INSERT INTO user_comments (name, comment)VALUES('{$name}','{$comment}')";

if (!mysqli_query($db_connection,$sql))
{
 die('Error: ' . mysqli_error($con));
 }
echo "1 record added";