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静态回调函数和非静态成员

[英]Static callback function and non-static member

原文 2014-03-11 00:45:26 1 2 c++/ qt/ static-methods/ static-members

I actually have a code (which I can't change) needs a static function as "callback function". 我实际上有一个代码（我无法改变）需要一个静态函数作为“回调函数”。

When I change the function to static, I can't access "this" and my class members then. 当我将函数更改为静态时，我无法访问“this”和我的类成员。 Also I can't pass "this" as parameter to function, again because I can't change the original SDK and definition files, so what can I do? 另外，我不能将“this”作为参数传递给函数，因为我无法更改原始SDK和定义文件，所以我该怎么办？

My code is in a class, one of class functions calls a function which needs a "static callback function" as parameter. 我的代码在一个类中，一个类函数调用一个需要“静态回调函数”作为参数的函数。 That "callback function" needs also to access "this" and other class members to process. 那个“回调函数”还需要访问“this”和其他类成员来处理。

What can I do? 我能做什么？ I'm using QT and VS 2012 as compiler. 我正在使用QT和VS 2012作为编译器。 Thanks 谢谢

2 个解决方案

A static function is in common with a global function, u can't image that u can use "this" in a global function, and not to mention class members... The only difference is a static function has a "namespace" as known as the calss name. 静态函数与全局函数是共同的，你无法想象你可以在全局函数中使用“this”，而不是提及类成员......唯一的区别是静态函数有一个“命名空间”作为被称为calss名称。 So, no matter what are you using or which compliler it is, you cannot use "this" or class members in a static function, it's just language features. 因此，无论您使用的是什么，或者使用哪种编译器，您都不能在静态函数中使用“this”或类成员，它只是语言功能。 And you should modify your code as Mike says. 你应该像迈克所说的那样修改你的代码。

If you use modern versions of C++ (11 or older) you may use std::bind . 如果您使用现代版本的C ++（11或更早版本），您可以使用std::bind 。 Or use boost:bind . 或者使用boost:bind 。