在使用Regex的python中，如何在带有短括号字符的字符串之后插入字符串？

Question

I have lines of data like this:

(ABCD:0.00825830327156463345,(LKSDJF:0.00000254996576400768,SDFADS:0.00917039554517301569):0.16367666117488463562,OIUO:0.00401845774067355072):0.0;
((OIUO:0.00298782818816040099,SDFADS:0.00148583412998809050):0.27857371651571366522,ABCD:0.00188545323182991121,LKSDJF:0.00799482946501124843):0.0;

And I am trying to use regex to insert a string after every every "):randomfloatingpoint_number". Sometimes the number is following by a comma and sometimes by a semicolon.

This is the code I wrote:

        line = re.sub(r"):[0-9\.])",r"\1 " + string, line)

But I get an error message that the parenthesis are unbalanced:

Traceback (most recent call last):
File "AssignFGbranches.py", line 31, in <module>
line = re.sub(r"):[0-9\.])",r"\1 " + string, line)
File "/usr/lib/python2.7/re.py", line 151, in sub
return _compile(pattern, flags).sub(repl, string, count)
File "/usr/lib/python2.7/re.py", line 242, in _compile
raise error, v # invalid expression
sre_constants.error: unbalanced parenthesis

What am I doing wrong?

Thanks!

Answer 1

You need to escape the brackets. Also, there is no number that is immediately followed by a closing brace. You may want something like this:

(\):[0-9.]+[;,])

This will match the following:

554517301569 ):0.16367666117488463562, OIUO

Answer 2

There are two issues. One is that the literal close parens needs to be escaped. The other is that the open parens for the group was missing:

re.sub(r"(\):[0-9\.]+)",r"\1 " + string, line1)