Python在一定数量的空行后打印文本

Question

I have certain text that is in the format such as:

    text:aaaaaaa
    text:bbbbbb
    text:cccccc

    text:ddddd
    text:eeeeee

    text:ffffff

I would like to print the text at:

    text:fffff

How can some python code be written that counts the two spaces between the text and prints the text at text:fffff

Answer 1

>>> with open("foo.txt") as fin:
...     any(x.isspace() for x in fin) # skip to 1st blank line
...     any(x.isspace() for x in fin) # skip to 2nd blank line
...     next(fin)
... 
True
True
'    text:ffffff\n'

To skip past n blank lines

>>> n = 2
>>> with open("t.txt") as fin:
...     for i in range(n):
...         any(x.isspace() for x in fin)
...     print next(fin)
... 
True
True
    text:ffffff

Answer 2

To do this way:

mydictonary = dict((k.strip(), v.strip()) for k,v in 
              (item.split(':') for item in s.split(' ')))

Here appy this things:

• whitespace remove from each pairs: (k.strip(), v.strip())
• split each part into "<key> ", " <value>" pairs: item.split(':')
• split the string into "<key> - <value>" pairs using s.split(' ')