[英]Symfony2 Form Handling
I am using forms to process my entity data via ajax to an api-method. 我正在使用表单通过ajax将我的实体数据处理为api方法。
My Type Class: 我的类型班:
/**
* @param FormBuilderInterface $builder
* @param array $options
*/
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder->add(
$builder->create('basicdata', 'form', array('virtual' => true))
->add('firstname', null, array('required' => true))
->add('lastname', null, array('required' => true))
);
$builder->add('contactdetails', new ContactdetailsType());
$builder->add('medialinks', new MedialinksType());
}
As u can see i seperate my form in 3 sections, one with basedata and 2 additional entities to keep contactdetails and medialinks. 如您所见,我将表单分为3个部分,其中一个包含baseata和2个其他实体以保留contactdetails和medialinks。
In my JavaScript i have the following listener on the create button: 在我的JavaScript中,创建按钮上具有以下侦听器:
$('#player_form_create').on('click', function(e){
e.preventDefault();
$.ajax({
type: "POST",
url: remotePathPlayerCreate,
data: $('.form').serialize()
});
});
According to chromes developer tool the POST data look like following: 根据chromes开发人员工具,POST数据如下所示:
player_form[basicdata][firstname]:Harvey
player_form[basicdata][lastname]:Specter
player_form[contactdetails][email]:h.specter@pearson.com
player_form[medialinks][website]: http://
In my API action i wanna handle the request and save a new player record: 在我的API操作中,我要处理请求并保存新的玩家记录:
public function cpostAction()
{
$player = new Player();
$form = $this->createForm(new PlayersType(), $player);
$form->handleRequest($this->getRequest());
if($form->isValid()){
$em = $this->getDoctrine()->getManager();
$em->persist($player);
$em->persist($player->getContactdetails());
$em->persist($player->getMedialinks());
$em->flush();
return $this->redirectView(
$this->generateUrl(
'get_player',
array('id' => $player->getId())
),
Codes::HTTP_CREATED
);
}
return array(
'processedForm' => $form
);
}
As u might allready know, the problem happens while i want to handle the request. 正如您可能已经知道的那样,问题是在我想处理请求时发生的。 I guess
$this->getRequest()
does not contain the POST data information in the format needed by the request handler. 我猜
$this->getRequest()
不包含请求处理程序所需格式的POST数据信息。
When i post data like this, i get a 500 with Expected argument of type \\"Symfony\\\\Component\\\\HttpFoundation\\\\Request\\", \\"array\\" given
. 当我这样发布数据时,我得到500,其
Expected argument of type \\"Symfony\\\\Component\\\\HttpFoundation\\\\Request\\", \\"array\\" given
。
How can i achieve that my POST data is submited as an request object? 我如何实现我的POST数据作为请求对象提交?
I ran into the same problem when building an app with Symfony on server side and AngularJS on client side. 使用服务器端的Symfony和客户端的AngularJS构建应用程序时,我遇到了相同的问题。 Handling the form this way worked:
以这种方式处理表单有效:
$content = $this->get('request')->getContent();
if (!empty($content)) { $params = json_decode($content, true); }
else { // return an error or whatever }
$defaultOptions = array('csrf_protection' => false);
$form = $this->createFormBuilder(null, $defaultOptions)
->add('email', 'email', array(
'constraints' => new Constraints\Email(array('message' => 'emailError'))
))
->getForm();
$form->submit($params);
if ($form->isValid()) {
...
}
Of course here I'm not using a type to create the form like you but the result is the same. 当然,这里我没有使用类型来创建像您一样的表单,但是结果是相同的。 This assumes that the request payload is something like this:
假设请求有效负载是这样的:
{email: 'test@example.com'}
好的,我找到了解决方案:根据页面如何使用Submit()函数处理表单提交,我现在使用$form->submit
将我的数组数据$form->submit
给表单:
$form->submit($this->getRequest()->request->get($form->getName()));
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