Count + Distinct SQL Query

Question

I have a research table like

researcher    award

 person1      award1
 person1      award2
 person2      award3

What I want to get is to count the award based on researcher but it researcher shouldnt be repeated. So in this example. The result should be

 2

Coz award1 and award2 is the same person + award3 which is a different person.

I already tried

SELECT count(award) from research where researcher=(select distinct(researcher) from researcher)

But it says

ERROR:  more than one row returned by a subquery used as an expression

So any alternative solution or changes?

Answer 1

This will give you researcher and count

select researcher, count(*) as c
from table
group by researcher

maybe you only want awarded ones?

select researcher, count(*) as c
from table
where award is not null
group by researcher

Answer 2

你可以做一个小组并计算不同的奖项。

SELECT count(distinct award) from research group by researcher

Answer 3

You just need to use GROUP BY :

SELECT    COUNT( DISTINCT Award ) AS awardCount 

FROM      Research 

GROUP BY  Researcher

Answer 4

select count(*) from (select researcher, count(*) 
from MyTable
group by researcher) as tempTable;