如何在php中使用所有mysql查询结果

Question

i need to get and update all results of the query, i get all the results but it updates only the first result, why? Thanks in advance.

$result=mysql_query(" SELECT text FROM sess WHERE dest='$name' AND mitt='$mitt' AND read='0'  ORDER BY idm  ");
 while($row = mysql_fetch_array($result)){
         $messages[]=$row[$i];
         $mess= mysql_real_escape_string($row[$i]);
         mysql_query(" UPDATE sess SET read='1' WHERE dest='$name' AND mitt='$mitt' AND text='$mess' ");
         $i++;
        }

Answer 1

You need to access the first index of your result row.

$result=mysql_query(" SELECT text FROM sess WHERE dest='$name' AND mitt='$mitt' AND read='0'  ORDER BY idm  ");
while($row = mysql_fetch_array($result)){
     $messages[]=$row[0];
     $mess= mysql_real_escape_string($row[0]);
     mysql_query(" UPDATE sess SET read='1' WHERE dest='$name' AND mitt='$mitt' AND text='$mess' ");
     $i++;
}

Note: that the functions you are using mysql_* are deprecated. There are some alternatives, mysqli_* being a direct replacement. Read more here

Note 2: Use the ID of the message to set the message as read. Using the content of the text is inefficient.

UPDATE sess SET read='1' WHERE message_id = $messageId

Answer 2

为什么不这样做呢

UPDATE sess SET read='1' WHERE dest='$name' AND mitt='$mitt' AND read='0' ?

Answer 3

try that :

  while($row = mysql_fetch_array($result)){

     mysql_query(" UPDATE sess SET read='1' WHERE dest='$name' AND mitt='$mitt' AND text='".$row['text']."' ");

    }

or this:

 while($row = mysql_fetch_assoc($result)){
 $id = mysql_real_escape_string($row['id']);
 mysql_query("UPDATE sess SET read='1' WHERE `id` = '$id' ");
}

Answer 4

Try this

$result=mysql_query("SELECT id ,text FROM sess WHERE dest='$name' AND mitt='$mitt' AND read='0'  ORDER BY idm  ");
while($row = mysql_fetch_assoc($result)){
     $messages[]=$row['text'];
     $id = mysql_real_escape_string($row['id']);
     mysql_query("UPDATE sess SET read='1' WHERE `id` = '$id' ");
     $i++;
}