正则表达式在没有斜杠的情况下选择斜杠之间的所有内容

Question

I have the following which is part of a url keyword/with/some/stuff/following

I need a regex (PHP) that would give me the same result as
explode('/', 'keyword/with/some/stuff/following');

In this case an array of matches like the following
array('keyword', 'with', 'some', 'stuff', 'following')

I've tried a few things including stuff from stackoverflow but without any luck

Answer 1

This would do it:

([^\/]+)

Working regex example

PHP

preg_match_all("/([^\/]+)/", "keyword/with/some/stuff/following", $matches);

$matches[1] =

array("keyword", "with", "some", "stuff", "following")