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循环以在R中创建特定矩阵

[英]Loop to create a specific matrix in R

I am not a programmer (in fact I am an economist). 我不是程序员(实际上我是经济学家)。 So, please, be generous with your answer. 因此,请大方回答。 I've just started to learn R - I've already read some tutorials about loops but I'm still stuck in this problem. 我刚刚开始学习R-我已经阅读了一些有关循环的教程,但是我仍然陷于这个问题。

My problem is: I need to create the matrix below using loop in R. 我的问题是:我需要使用R中的循环创建下面的矩阵。

$$
\begin{bmatrix}
0.1 & 0.9 & 0 & 0 & 0\\ 
0.1 & 0 & 0.9 & 0 & 0\\ 
0 & 0.1 & 0 & 0.9 &0 \\ 
0 & 0 & 0.1 & 0 &0.9 \\ 
0 & 0 & 0 & 0.1 & 0.9
\end{bmatrix}
$$

I would greatly appreciate if someone could explain me step by step 如果有人可以逐步解释我,我将不胜感激

Typically, one makes a matrix by wrapping a vector of values by row ( byrow=TRUE ) or the default, by column ( byrow=FALSE ) 通常,通过按行( byrow=TRUE )或默认值按列( byrow=FALSE )包装值的向量来构成矩阵

matrix(
    c(0.1,0.9,0,0,0,
    0.1,0,0.9,0,0,
    0,0.1,0,0.9,0,
    0,0,0.1,0,0.9,
    0,0,0,0.1,0.9),
    nrow=5,ncol=5,
    byrow=TRUE
)

Result: 结果:

     [,1] [,2] [,3] [,4] [,5]
[1,]  0.1  0.9  0.0  0.0  0.0
[2,]  0.1  0.0  0.9  0.0  0.0
[3,]  0.0  0.1  0.0  0.9  0.0
[4,]  0.0  0.0  0.1  0.0  0.9
[5,]  0.0  0.0  0.0  0.1  0.9

Alternatively, and I'm not sure why you would need to do this, you could set up a loop where the index can be used to give the row and column indices: 另外,我不确定为什么需要这样做,您可以设置一个循环,在该循环中可以使用索引来提供行索引和列索引:

x <- c(0.1,0.9,0,0,0,
    0.1,0,0.9,0,0,
    0,0.1,0,0.9,0,
    0,0,0.1,0,0.9,
    0,0,0,0.1,0.9)
m <- matrix(NaN, 5, 5)
for(i in seq(length(m))){
    ROW <- (i-1) %/% ncol(m) + 1
    COL <- (i-1) %% ncol(m) + 1
    m[ROW, COL] <- x[i]
}
m

Result: 结果:

     [,1] [,2] [,3] [,4] [,5]
[1,]  0.1  0.9  0.0  0.0  0.0
[2,]  0.1  0.0  0.9  0.0  0.0
[3,]  0.0  0.1  0.0  0.9  0.0
[4,]  0.0  0.0  0.1  0.0  0.9
[5,]  0.0  0.0  0.0  0.1  0.9

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