如何在php中将ISO8601转换为日期格式

Question

How to convert this ( in ISO8601 format ): 2014-03-13T09:05:50.240Z

To this ( in MySQL DATE format ): 2014-03-13

in php?

Answer 1

try this

$date = '2014-03-13T09:05:50.240Z';

$fixed = date('Y-m-d', strtotime($date));

The complete date function documentation can be found here: http://php.net/manual/en/function.date.php

The PHP function "strtotime" does nothing else then converting your timestring into an unix timestamp.

Hope I could help :)

Ps: Just in case strtotime will return 0 try using this:

$date = '2014-03-13T09:05:50.240Z';

$fixed = date('Y-m-d', strtotime(substr($date,0,10)));

Answer 2

Since PHP 5.2.0 you can do it using OOP and DateTime() as well (of course if you prefer OOP):

$now = new DateTime("2014-03-13T09:05:50.240Z");
echo $now->format('Y-m-d');    // MySQL datetime format

Answer 3

There is no reason to use the inefficient time functions. The most efficient way is to simply extract the first 10 characters:

substr($date,0,10)

People, that are really coding for year ≥10000, can use:

substr($date,0,strpos($date,"T"))

Answer 4

Simply convert datetime description into a Unix timestamp using with strtotime and then five format using Date Formats

Try it will surely work for you.

$date = '2014-03-13T09:05:50.240Z';

$fixed = date('Y-m-d', strtotime($date));

Answer 5

For those using Carbon (php library), the parse() works quite well:

Carbon::parse($date)

https://carbon.nesbot.com/docs/

Answer 6

Today I have published an interitty/utils package that deals with, among other things, the ISO-8601 format and perhaps all permutations of this standard.

I hope it will help you too.

$dateTimeFactory = new Interitty\Utils\DateTimeFactory();
$dateTime = $dateTimeFactory->createFromIso8601('1989-12-17T12:00:00Z');