PHP（Regex）-将网址部分与括号匹配

Question

I am pretty new to regex (only really started looking seriously to it a few hours ago) and even if it is not going that bad... I am having a bad time matching parenthesis.

Here's what I have / want:

$p = "#(\/new_arrivals\/[a-zA-Z0-9_]+|\/\(offset\)\/([0-9][0-9]|[0-9][0-9][0-9]))$# i";
$s = "http://www.example.com/abc/cba/new_arrivals/(offset)/29";

I would like to match /(offset)/29 ... but I can't seem to be able to make it match the parenthesis even if I did try to escape them.

Also.. the number 29... starts into 29 and goes up till 500. Is there any simpler way to make it match 2 or 3 numbers instead all of this ([0-9][0-9]|[0-9][0-9][0-9]) ?

Answer 1

Use this regex:

\/\(offset\)\/\d{2,3}

Demo: http://regex101.com/r/tZ7zS4

Answer 2

\\/\\(*[Az]+\\)*\\/[0-9]+$

matches: /(offset)/29

\\/[Az]+\\/[0-9]+$

matches: /offset/29

Hope it helps