使用Java在所有标签名称相同时如何读取xml文件

Question

<?xml version="1.0"?>
<test name="test">
    <params>
        <param name="credentials" type="list">
            <item>
                <property name="username" value="abc"/>
                <property name="password" value="cba"/>
            </item>
            <item>
                <property name="username" value="user1"/>
                <property name="password" value="pass1"/>
            </item>
        </param>
        <param name="otherKey" value="singleValue"/>
    </params>

I can have the param tag where one has items or where one is empty. anyway my question is how to i read the <item> tags using java? (there maybe more param tags later with more items)one way is taking a nodelist of tag <param> . then taking nodelist of tag <item> for those param which has child nodes and using the getelementbyTag() .

is there any other way where the second nodelist can be avoided?

if yes then how??

Answer 1

To avoid the second nodelist item you can specify the index of the nodelist you want. which in this case I assume you only want to get the first nodelist. The code would have to be as follows.

String username; String password;

NodeList nList = doc.getElementsByTagName("param")

Node nNode = nList.item(0); // This will point to just the first nodelist item

if (nNode.getNodeType() == Node.ELEMENT_NODE)
{ Element eElement =(Element) nNode;

  username=eElement.getAttribute("username"); 

 password=eElement.getAttribute("password"); 

}