[英]How to convert shell script in one line and execute it from Python subprocess?
I have my below simple shell script which I am trying to convert in one single line so that I can execute it from my Python program using subprocess - 我有下面的简单shell脚本,我试图将其转换为一行,以便可以使用子进程从我的Python程序中执行它-
#!/bin/bash
set -e
COUNT=60 #number of 10 second timeouts in 10 minutes
SUM_SYNCS=0
SUM_SYNCS_BEHIND=0
HOSTNAME=$hostname
echo $HOSTNAME
while [[ $COUNT -ge "0" ]]; do
#send the request, put response in variable
DATA=$(wget -O - -q -t 1 http://$HOSTNAME:8080/beat)
#grep $DATA for syncs and syncs_behind
SYNCS=$(echo $DATA | grep -oE 'num_syncs: [0-9]+' | awk '{print $2}')
SYNCS_BEHIND=$(echo $DATA | grep -oE 'num_syncs_behind: [0-9]+' | awk '{print $2}')
echo $SYNCS
echo $SYNCS_BEHIND
#verify conditionals
if [[ $SYNCS -gt "8" && $SYNCS_BEHIND -eq "0" ]]; then exit 0; fi
#decrement the counter
let COUNT-=1
#wait another 10 seconds
sleep 10
done
I converted the above script in one line like this - 我将上述脚本转换成这样的一行-
jsonStr = {"script": "#!/bin/bash\nset -e\n\nCOUNT=60 #number of 10 second timeouts in 10 minutes\nSUM_SYNCS=0\nSUM_SYNCS_BEHIND=0\nHOSTNAME=$hostname\t\n\necho $HOSTNAME\n\nwhile [[ $COUNT -ge \"0\" ]]; do\n\n#send the request, put response in variable\nDATA=$(wget -O - -q -t 1 http://$HOSTNAME:8080/beat)\n\n#grep $DATA for syncs and syncs_behind\nSYNCS=$(echo $DATA | grep -oE 'num_syncs: [0-9]+' | awk '{print $2}')\nSYNCS_BEHIND=$(echo $DATA | grep -oE 'num_syncs_behind: [0-9]+' | awk '{print $2}')\n\necho $SYNCS\necho $SYNCS_BEHIND\n\n#verify conditionals\nif [[ $SYNCS -gt \"8\" && $SYNCS_BEHIND -eq \"0\" ]]; then exit 0; fi\n\n#decrement the counter\nlet COUNT-=1\n\n#wait another 10 seconds\nsleep 10\n\ndone\n"}
And I am trying to execute this using Python subprocess but everytime I am getting an error - 我试图使用Python子进程执行此操作,但是每次遇到错误时,
File "C:\Python27\lib\json\__init__.py", line 326, in loads
return _default_decoder.decode(s)
File "C:\Python27\lib\json\decoder.py", line 366, in decode
obj, end = self.raw_decode(s, idx=_w(s, 0).end())
TypeError: expected string or buffer
Below is my full Python code which I am trying out - 以下是我正在尝试的完整Python代码-
jsonStr = {"script": "#!/bin/bash\nset -e\n\nCOUNT=60 #number of 10 second timeouts in 10 minutes\nSUM_SYNCS=0\nSUM_SYNCS_BEHIND=0\nHOSTNAME=$hostname\t#\n\necho $HOSTNAME\n\nwhile [[ $COUNT -ge \"0\" ]]; do\n\n#send the request, put response in variable\nDATA=$(wget -O - -q -t 1 http://$HOSTNAME:8080/beat)\n\n#grep $DATA for syncs and syncs_behind\nSYNCS=$(echo $DATA | grep -oE 'num_syncs: [0-9]+' | awk '{print $2}')\nSYNCS_BEHIND=$(echo $DATA | grep -oE 'num_syncs_behind: [0-9]+' | awk '{print $2}')\n\necho $SYNCS\necho $SYNCS_BEHIND\n\n#verify conditionals\nif [[ $SYNCS -gt \"8\" && $SYNCS_BEHIND -eq \"0\" ]]; then exit 0; fi\n\n#decrement the counter\nlet COUNT-=1\n\n#wait another 10 seconds\nsleep 10\n\ndone\n"}
j = json.loads(jsonStr)
print "start"
proc = subprocess.Popen(j['script'], shell=True, stdout=subprocess.PIPE, stderr=subprocess.PIPE, executable='/bin/bash')
(stdout, stderr) = proc.communicate()
print stdout
print stderr
print "end"
What is wrong in my shell script which I have converted in one line? 我已将一行转换的shell脚本出了什么问题? Any thoughts?
有什么想法吗?
NOTE: All my other shell scripts are working which are also in one liner from the same Python subprocess call, only this is having some problem. 注意:我所有其他的shell脚本都在工作,这些脚本也在同一Python子进程调用的同一行中,只有这样才有问题。
The error you are getting is from json.loads(jsonStr)
. 您收到的错误来自
json.loads(jsonStr)
。 json.loads
require a str
or unicode
not a dict
. json.loads
需要str
或unicode
而不是dict
。 jsonStr
is already a dict
you don't need json.loads
jsonStr
已经是一个dict
,你不需要json.loads
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