如何在另一个PHP页面中获取列表框值

Question

i think i am doing some mistake in my code. can someone please correct me. how to get the list box values in another page.

print "<form method=\"post\" action=\"fetch_test.php\">";
print "Report From: ";
print "<select name=fromdate[]>";
print "<option selected=\"selected\">Date</option>";
print "<option value=01>01</option>";
print "<option value=02>02</option>";
print "<option value=03>03</option>";
print "</select>";

print "<select name=frommonth[]>";
print "<option selected=\"selected\">Month</option>";
print "<option value=jan>Jan</option>";
print "<option value=feb>Feb</option>";
print "<option value=mar>Mar</option>";
print "</select>";

print "<br><br>";
print "<input type=submit>";
print "</form>";

fetch_test.php contains below code.

<?php
print $_POST['fromdate'];
print $_POST['frommonth'];
?>

Answer 1

You are using the name as an Array .

Fixed code:

print "<form method=\"post\" action=\"fetch_test.php\">";
print "Report From: ";
print "<select name=fromdate>";
print "<option selected=\"selected\">Date</option>";
print "<option value=01>01</option>";
print "<option value=02>02</option>";
print "<option value=03>03</option>";
print "</select>";

print "<select name=frommonth>";
print "<option selected=\"selected\">Month</option>";
print "<option value=jan>Jan</option>";
print "<option value=feb>Feb</option>";
print "<option value=mar>Mar</option>";
print "</select>";

print "<br><br>";
print "<input type=submit>";
print "</form>";

Answer 2

You stored it in an array, so call it in an array also.

<?php

print $_POST['fromdate'][$yournumbervalue];
print $_POST['frommonth'][$yournumbervalue];

?>

Answer 3

尝试引用您的select标记名称，您希望使用<select name="fromdate[]">来获取数组，并且您想使用<select from="fromdate">来获取单个值。

Answer 4

Unless there are more than one name='fromdate' or name='frommonth' , you don't need the [] .

Just try normal:

print "<select name='fromdate'>";

Make sure you put ' around the name attribute!

Then use:

$_POST['fromdate'];

At the moment you're putting it into an array, so if you want to keep it the way it is, use:

foreach ($fromdate as $date){
  echo $date;
}