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将XML转换为ac#对象

[英]Converting XML into a c# object

It is complicating me convert an XML to an object in C#. 这使我很难将XML转换为C#中的对象。

I want to convert an XML consisting of a list of objects 'Regla' with a series of fields (idRegla, DateFrom, DateTo, and a list of exceptions that may not appear). 我想转换一个XML,该XML包含对象“ Regla”的列表以及一系列字段(idRegla,DateFrom,DateTo和可能未出现的异常列表)。

I'm going crazy, I do not think it's that hard ... 我快疯了,我不认为这很难...

Here is the XML: 这是XML:

<ListaReglas>
  <REGLA>
    <idRegla>2</idRegla>
    <DateFrom>2013-12-01T00:00:00</DateFrom>
    <DateTo>2015-07-25T00:00:00</DateTo>
    <Excepciones>
      <FECHA>2013-12-25T00:00:00</FECHA>
    </Excepciones>
  </REGLA>
  <REGLA>
    <idRegla>4</idRegla>
    <DateFrom>2013-12-01T00:00:00</DateFrom>
    <DateTo>2015-07-25T00:00:00</DateTo>
    <Excepciones>
      <FECHA>2013-12-25T00:00:00</FECHA>
    </Excepciones>
  </REGLA>
  <REGLA>
    <idRegla>5</idRegla>
    <DateFrom>2013-12-01T00:00:00</DateFrom>
    <DateTo>2015-07-25T00:00:00</DateTo>
    <Excepciones>
      <FECHA>2013-12-25T00:00:00</FECHA>
    </Excepciones>
  </REGLA>
  <REGLA>
    <idRegla>7</idRegla>
    <DateFrom>2013-11-19T00:00:00</DateFrom>
    <DateTo>2015-12-19T00:00:00</DateTo>
  </REGLA>
</ListaReglas>

Here is my class: 这是我的课:

        [Serializable]
        [XmlTypeAttribute(AnonymousType = true)]
        public class ReglaRangoResult
        {
            [XmlElement(ElementName = "idRegla", IsNullable = false)]
            public int idRegla { get; set; }

            [XmlElement(ElementName = "DateFrom", IsNullable = false)]
            public DateTime DateFrom { get; set; }

            [XmlElement(ElementName = "DateTo", IsNullable = false)]
            public DateTime DateTo { get; set; }

            [XmlElement(ElementName = "Excepciones", IsNullable = true)]
            public List<DateTime> Excepciones { get; set; }

            [XmlIgnore]
            public int Peso { get; set; }
        }

And this is my code: 这是我的代码:

       [...]
       List<ReglaRangoResult> listaReglas = new List<ReglaRangoResult>();
       XmlDoc xmlDoc = new XmlDoc(rdr.GetString(0));

       foreach (XmlNode xmlNode in xmlDoc.SelectNodes("//ListaReglas/REGLA"))
       {
            listaReglas.Add(XmlToObject<ReglaRangoResult>(xmlNode.OuterXml));
       }
       [...]


        public static T XmlToObject<T>(string xml)
        {
            using (var xmlStream = new StringReader(xml))
            {
                var serializer = new XmlSerializer(typeof(T));
                return (T)serializer.Deserialize(XmlReader.Create(xmlStream));
            }
        }

I don't understand what I'm doing wrong. 我不明白我在做什么错。 Is the ReglaRangoResult misconfigured class? ReglaRangoResult是否配置错误的类? What is missing? 什么东西少了? What is left? 剩下什么?

EXCEPTION RETURNED: 例外返回:

'Error reflecting type 'dllReglasNegocioMP.ReglaRangoResult' '反映类型为'dllReglasNegocioMP.ReglaRangoResult的错误'

In Visual Studio 2013 you can take the XML and select "Edit / Paste special / Paste XML as Classes". 在Visual Studio 2013中,您可以采用XML并选择“编辑/特殊粘贴/将XML作为类粘贴”。 When you have done that you can use use XmlSerializer to serialize and deserialize in an easy way. 完成后,可以使用XmlSerializer以一种简单的方式进行序列化和反序列化。

 var serializer = new System.Xml.Serialization.XmlSerializer(typeof(MyPastedClass));
 MyPastedClass obj;
 using (var xmlStream = new StringReader(str))
 {
      obj = (MyPastedClass)serializer.Deserialize(xmlStream);
 }

Take my class listed bellow. 以我班上列出的波纹管为例。 You can serilialize your object to real XML and compare it. 您可以将对象序列化为真实的XML并进行比较。

using System.Diagnostics.Contracts;
using System.Globalization;
using System.IO;
using System.Text;
using System.Xml;
using System.Xml.Serialization;

namespace VmsSendUtil
{
    /// <summary> Serializes and Deserializes any object to and from string </summary>
    public static class StringSerializer
    {
        ///<summary> Serializes object to string </summary>
        ///<param name="obj"> Object to serialize </param>
        ///<returns> Xml string with serialized object </returns>
        public static string Serialize<T>(T obj)
        {
            Contract.Ensures(!string.IsNullOrEmpty(Contract.Result<string>()));

            var stringSerializer = new StringSerializer<T>();
            return stringSerializer.Serialize(obj);
        }

        /// <summary> Deserializes object from string. </summary>
        /// <param name="xml"> String with serialization XML data </param>
        public static T Deserialize<T>(string xml)
        {
            Contract.Requires(!string.IsNullOrEmpty(xml));
            Contract.Ensures(!Equals(Contract.Result<T>(), null));

            var stringSerializer = new StringSerializer<T>();
            return stringSerializer.Deserialize(xml);
        }
    }

    /// <summary> Serializes and Deserializes any object to and from string </summary>
    public class StringSerializer<T>
    {
        [ContractInvariantMethod]
        private void ObjectInvariant()
        {
            Contract.Invariant(_serializer != null);
        }

        private readonly XmlSerializer _serializer = new XmlSerializer(typeof(T));

        ///<summary> Serializes object to string </summary>
        ///<param name="obj"> Object to serialize </param>
        ///<returns> Xml string with serialized object </returns>
        public string Serialize(T obj)
        {
            Contract.Ensures(!string.IsNullOrEmpty(Contract.Result<string>()));

            var sb = new StringBuilder();
            using (var sw = new StringWriter(sb, CultureInfo.InvariantCulture))
            {
                var tw = new XmlTextWriter(sw) { Formatting = Formatting.Indented };
                _serializer.Serialize(tw, obj);
            }
            string result = sb.ToString();
            Contract.Assume(!string.IsNullOrEmpty(result));
            return result;
        }

        /// <summary> Deserializes object from string. </summary>
        /// <param name="xml"> String with serialization XML data </param>
        public T Deserialize(string xml)
        {
            Contract.Requires(!string.IsNullOrEmpty(xml));
            Contract.Ensures(!Equals(Contract.Result<T>(), null));

            using (var stringReader = new StringReader(xml))
            {
                // Switch off CheckCharacters to deserialize special characters
                var xmlReaderSettings = new XmlReaderSettings { CheckCharacters = false };

                var xmlReader = XmlReader.Create(stringReader, xmlReaderSettings);
                var result = (T)_serializer.Deserialize(xmlReader);
                Contract.Assume(!Equals(result, null));
                return result;
            }
        }
    }
}

you get an exception that have an hierarchy that you do not define in your code. 您将获得一个异常,该异常的层次结构未在代码中定义。 if you'll set the right hierarchy it will work. 如果您设置正确的层次结构,它将起作用。

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