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使用PHP从下拉列表中显示选定值的记录

[英]Display a record for a selected value from drop down using PHP

I have populated a drop down with database values. 我已经用数据库值填充了一个下拉列表。 Now I want to display a record from the database for a selected value in the drop down. 现在,我想在数据库中显示下拉列表中选定值的记录。

For example, the drop down contains: 例如,下拉列表包含:

1
2
3
4

If the selected value is 1 , it will show the record for id 1 below the drop down. 如果选择的值为1 ,它将在下拉列表下方显示ID为1的记录。

id | name | address | date
1  | jay  | India   | 23/2/1970

How can I do this? 我怎样才能做到这一点?

Name your select tag as id: 将您的选择标签命名为ID:

<form action="" method="POST">
    <select name=id>
        <option value=1></option>
        <option value=2></option>
        <option value=3></option>
    </select>
</form>

<?php
    $select = $_POST['id'];
    $record = "select * from table_name where id=$select";
    $record1 = mysql_query($record);
?>`

Here is your SQL code: 这是您的SQL代码:

select * from tb_first
  where id =1;

A demo is at fiddle, http://sqlfiddle.com/#!2/c13e9 . 演示位于http://sqlfiddle.com/#!2/c13e9

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