C ++中的数组和函数

Question

I am working with array of chars. My function is expected to return an array. Then I expect to assign that array to a different char array .

eg I have

char somechar[50];

in Class declaration, it is private.

I defined a get method as :

char getsomechar(){
    return somechar;
}

in my main function, I am trying to: access it assign as:

char newchar[]=getsomechar();

I was given return type and function type do not match. So I corrected second line to:

char *getsomechar(){
    return somechar;
}

However I am still having initialization with {...} expected for aggregate object error. I read some pages and saw that you cannot pass array by value in C++. I can't use array library. How do I do it with pointers/references?

Answer 1

You are essentially returing a pointer to the array in your funciton:

return somechar;  //this is the starting address of the array

So, you should declare a char* and assign the starting address of the array to it, like so :

char* newchar=getsomechar();

and now you can access this pointer, like an array by indexing:

for(int i=0;i<ARRAY_SIZE;i++)
{
    newchar[i] = value // whatever operation you want to do here
}