正则表达式-匹配以获取\\ r \\ n之前和之后的单词

Question

Why doesn't my regex match?

SOURCE[\s]*[:]*[\s]*(\r\n|\r|\n)*[\[#x3000\]]*[A-Za-z \!\.\-]*

Text

\xa0SOURCE:\r\nHult International Business School\r\n\r\n\r\n\r\n\r\nSUBJECT: ENTREPRENEURSHIP (92%); 

My regex tries. it seems to work nearly okay here. http://regex101.com/r/aB7nJ2

For some reason, only a [\\s] captured the \\r\\n. i don't understand why. using [\\s]* solved it.

Answer 1

Is your regex pattern defined with a raw string ? If so, it should match:

In [25]: import re

In [26]: text = '\xa0SOURCE:\r\nHult International Business School\r\n\r\n\r\n\r\n\r\nSUBJECT: ENTREPRENEURSHIP (92%);'

In [27]: re.search(r'SOURCE[\s]*[:]*[\s]*(\r\n|\r|\n)*[\[#x3000\]]*[A-Za-z \!\.\-]*', text)
Out[27]: <_sre.SRE_Match at 0xb0bffa0>

From the docs :

Raw string notation (r"text") keeps regular expressions sane. Without it, every backslash ('\\') in a regular expression would have to be prefixed with another one to escape it.

Answer 2

缺少一些转义？

SOURCE[\s]*[:]*[\s]*(\\r\\n|\\r|\\n)*[\[#x3000\]]*[A-Za-z \!\.\-]*