[英]Continually catch exception in python
I need to keep catching an exception while indexing a list throws a IndexError exception, for example: 在索引列表引发IndexError异常时,我需要不断捕获异常,例如:
l = []
while((l[3]) throws IndexError):
//Add more data to the list
l += [3]
How can I keep checking to see if the method call has thrown an exception without having nested a nested try/catch block? 如何在不嵌套嵌套的try / catch块的情况下继续检查方法调用是否引发了异常?
It depends what you would like to extend your list with. 这取决于您想要扩展列表的范围。 Assuming 'None' you could do it like this:
假设“无”,您可以这样做:
l = []
while True:
try:
l[3] = 'item'
break
except IndexError:
l.extend([None])
print l # [None, None, None, 'item']
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